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Mrrafil [7]
3 years ago
13

What is the Momentum of a ball that has a mass of 0.5 kg and a velocity of 20 m/s?

Physics
1 answer:
Zarrin [17]3 years ago
8 0
P (momentum) = mass x velocity
p = .5 x 20
p = 10
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The diagram shows a spectrometer being used to analyze a sample of a solution.
fredd [130]

Answer

B. X

A plate of glass or metal ruled with very close parallel lines, producing a spectrum by diffraction and interference of light.

diffraction grating is an optical component that splits and diffracts light into several beams travelling in different directions. The light emerges with its colours separated.

4 0
3 years ago
Read 2 more answers
A particle with a charge of 2e moves between two points which have a potential difference of 75V. What is the change in potentia
Sonbull [250]
Electric potential energy is defined as Ep=Q*V where Q is the magnitude of the charge and V is the potential difference. So when a charge moves between the points that have a potential difference, it's energy changes. 

In our case: 

Q=2e=2*(-1.6*10^-19) C
V=75 V

Ep=(-3.2*10^-19)*75

Ep=-2.4*10^-17 J

The change in potential energy of the charge is -2.4*10^-17 J 
5 0
3 years ago
The chart shows data for a moving object.
Ipatiy [6.2K]

Answer:

number 2

Explanation:

8 0
3 years ago
Some of the highest tides in the world occur in the Bay of Fundy on the Atlantic Coast of Canada. At Hopewell Cape the water dep
Nady [450]

Answer:

(a) 1.939 m/h

(b) 0.926 m/h

(c) -0.315 m/h

(d) -1.21 m/h

Explanation:

Here, we have the water depth given by the function of time;

D(t) = 7 + 5·cos[0.503(t-6.75)]

Therefore, to find the velocity of the depth displacement with time, we differentiate the given expression with respect to time as follows;

D'(t) = \frac{d(7 + 5\cdot cos[0.503(t-6.75)])}{dt}

= 5×(-sin(0.503(t-6.75))×0.503

= -2.515×(-sin(0.503(t-6.75))

= -2.515×(-sin(0.503×t-3.395))

Therefore we have;

(a) at 5:00 AM = 5 -  0:00 = 5

D'(5) =  -2.515×(-sin(0.503×5-3.395)) = 1.939 m/h

(b) at 6:00 AM = 6 -  0:00 = 6

D'(5) =  -2.515×(-sin(0.503×6-3.395)) = 0.926 m/h

(c) at 7:00 AM = 7 -  0:00 = 7

D'(5) =  -2.515×(-sin(0.503×7-3.395)) = -0.315 m/h

(d) at Noon 12:00 PM = 12 -  0:00 = 12

D'(5) =  -2.515×(-sin(0.503×12-3.395)) = -1.21 m/h.

4 0
3 years ago
If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?
olya-2409 [2.1K]
Given: Mass m = 44 Kg;      Velocity v = 10 m/s

Required: Kinetic energy K.E = ?

Formula: K.E = 1/2 mv²

               K.E 1/2 (44 Kg)(10 m/s)²

               K.E = 2,200 Kg.m²/s²

               K.E = 2,200 J Answer is A
8 0
3 years ago
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