Answer:
I = 4.28 [amp]
Explanation:
To solve this type of problems we must have knowledge of the law of ohm, which tells us that the voltage is equal to the product of resistance by current.
Initial data:
v = 1.5 [volt]
R = 0.35 [ohms]
v = I * R
therefore:
I = 1.5 / 0.35
I = 4.28 [amp]
Magnets are attracted when each of the different sides, most commonly known as "North" and "South", are facing each other. They repel when North and North, or South and South are facing each other.
Explanation:
Given that,
Mass, m = 0.08 kg
Radius of the path, r = 2.7 cm = 0.027 m
The linear acceleration of a yo-yo, a = 5.7 m/s²
We need to find the tension magnitude in the string and the angular acceleration magnitude of the yo‑yo.
(a) Tension :
The net force acting on the string is :
ma=mg-T
T=m(g-a)
Putting all the values,
T = 0.08(9.8-5.7)
= 0.328 N
(b) Angular acceleration,
The relation between the angular and linear acceleration is given by :
(c) Moment of inertia :
The net torque acting on it is, , I is the moment of inertia
Also,
So,
Hence, this is the required solution.
The new period is D) √2 T
<h3>Further explanation</h3>
Let's recall Elastic Potential Energy and Period of Simple Pendulum formula as follows:
where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>
where:
<em>T = period of simple pendulum ( s )</em>
<em>L = length of pendulum ( m )</em>
<em>g = gravitational acceleration ( m/s² )</em>
Let us now tackle the problem!
<u>Given:</u>
initial length of pendulum = L₁ = L
initial mass = M₁ = M
final length of pendulum = L₂ = 2L
final mass = M₂ = 2M
initial period = T₁ = T
<u>Asked:</u>
final period = T₂ = ?
<u>Solution:</u>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity