Question

Consider a solution containing 3.54 mM of an analyte, X, and 1.23 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 3275 and 10829, respectively. Determine the response factor for X relative to S.F=To determine the concentration of X in an unknown solution, 1.00 mL of 8.27 mM S was added to 5.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After chromatographic separation, this solution gave peak areas of 5389 and 4627 for X and S, respectively. Determine the concentration of S in the 10.0 mL solution.[S]=Determine the concentration of X in the 10.0 mL solution.[X]=Determine the concentration of X in the unknown solution.[X]=

Answer 1

Answer:

The response factor for X relative to S is 0,105

Concentration of X in the unknown solution is: 18,3mM

Explanation:

The response factor of X is:

RF x = peak area / concentration = 925

And of S:

RF s = 10829 / 1,23 = 8804

The response factor for X relative to S is:

RRF = 925/8804 = 0,105

Concentration of S in the unknown solution is:

8,27mM×$\frac{1,00mL}{10,0mL}$ = 0,827mM

-Because the 1,00 mL of S was diluted from 1,00mL to 10,0mL-

Using the RRF formula:

Conc X = Peak area X* Concentration B / peak area S * RRF

[X] = 5389*0,827mM / 4627*0,105

[X] = 9,17mM in the 10,0mL solution.

In the unknown solution:

9,17mM×$\frac{10,0mL}{5,00mL}$ = 18,3mM

I hope it helps!