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Lady bird [3.3K]
3 years ago
9

Tia has a sample of pure gold (Au). She weighed the sample and the result was 62.4 grams. Tia wants to determine the number of a

toms in the sample. Calculate the number of atoms in 62.4 g of pure gold.
Chemistry
1 answer:
Marta_Voda [28]3 years ago
7 0
I hope you are able to find your answer through the guidance of this site as I have yet to cover this topic in chemistry: http://scientifictutor.org/1021/chem-how-to-convert-between-grams-and-molecules/
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Which type of statement provides a possible answer to a scientific question
Morgarella [4.7K]

Answer:

A hypothesis is a possible explanation for a set of observations or an answer to a scientific question. A hypothesis must be testable and measurable.

Explanation:

4 0
2 years ago
Consider the set of isoelectronic atoms and ions a2–, b–, c, d+, and e2+. which arrangement of relative radii is correct?
faust18 [17]
The term isoelectronic atoms means that if the given atoms are neutral, they would have the same number of electrons, which is relative to their sizes. Ions with positive charges are called cations, losing electrons. On the other hand, ions with negative charges are called anions, gaining electrons. The more electrons that the atoms have, the bigger it is in size. Hence, the arrangement of the radii of the atoms would have to be,

      e²⁺, d⁺, c , b⁻, a⁻

The arrangement is from smallest to largest.
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3 years ago
The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i
Rus_ich [418]

Answer: a)  The concentration after 8.8min is 0.17 M

b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) concentration after 8.8 min:

8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}

\log\frac{0.25}{a-x}=0.15

\frac{0.25}{a-x}=1.41

(a-x)=0.17M

b) for concentration to decrease from 0.25M to 0.15M

t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20

t=687s

7 0
3 years ago
Arrange the sublevels in ascending order by the number of electrons they can contain. p sublevel s sublevel d sublevel f subleve
inn [45]

Electronic configuration of the atom describes  the arrangemnet of electrons in different shells and subshells ( sublevels).

Now , there are 4 types of sublevels: s, p , d and f . These sublevels have orbital which are spaces with high probability of having an electron and each orbital can have maximum 2 electrons.

Therefore,

s-sublevel has 1 orbital - it can have maximum 2 electrons.

p-sublevel has 3 orbitals - it can have maximum 6 electrons

d-sublevel has 5 orbitals - it can have maximum 10 electrons

f-sublevel has 7 orbitals - it can have maximum 14 electrons.

Hence, the acsending order of sublevels in terms of maximum number of electrons is:

<h2>s < p < d < f</h2>
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3 years ago
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What are some examples of lipids?
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Saturated fat, milk, cheese, and meat.
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