Answer:
Hi there! After reading each of these descriptions of snow and sleet, I believe that Brad's description is the most accurate and complete. Alanna seems to be describing snow and hail, Candace has not provided an accurate description of snow, and Jim's description is completely inaccurate. Brad provides the best description.
I hope this helps you! Take care and have a great day - Mani :)
Answer:
Oceanic trenches
Explanation:
Oceanic Trenches are hemispheric-scale long but narrow topographic depressions of the sea floor
Answer:
atomic structure - The nucleus is at the center of an atom, where most of the charge and mass are concentrated
protons - a stable subatomic particle occurring in all atomic nuclei, with a positive electric charge equal in magnitude to that of an electron, but of opposite sign.
neutrons - a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.
electrons - a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
atom vs. ion - an atom is the basic unit of a chemical element, and an ion is an atom or molecule with a net electric charge due to the loss or gain of one or more electrons. See also cation, anion.
Mass number - total number of protons, and neutrons in an atom.
Explanation:
i hope this is what you were looking for.
Answer:
See explanation
Explanation:
The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.
On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.
W=0.360
p=1.18g/mL
pH=2.12
v=14.0 L
M(HCl)=36.46 g/mol
v₀-?
1) pH=-lg[H⁺]
[H⁺]=c(HCl)=10^(-pH)
n(HCl)=v[H⁺]=v*10^(-pH)
2) n(HCl)=m(HCl)/M(HCl)=wv₀p/M(HCl)
3) v*10^(-pH)=wv₀p/M(HCl)
v₀=v*10^(-pH)M(HCl)/(wp)
v₀=14.0*10^(2.12)*36.46/(0.360*1.18)=9.115 mL
Approximately 9.1 mL of concentrated solution required.
