Answer:
The correct answer is 2.33g of 
, A
Explanation:
We can use basic stoich to get this question.
To start, lets convert our grams to moles in order to use our equation. 5.38g of 
moles.
We then can use our molar ratio of 13:10. Simply divide by our molar ratio in order to go from moles of 
to moles of . This gets us 0.129335 moles of .
Now lets convert to grams of by multiplying by the molar mass of . 
of
The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.
The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an
individual gas in a mixture and n is total moles of the gas mixture. We
know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in
total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate
the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole
fraction of gas Y (x) and the total pressure (P) to calculate the
partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =
2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =
1.6 atm.
Answer
Explanation:
can you please put it in boxes so i can find out the answer
Answer: I think its C or B
Explanation: Hope this was helpful....
