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3 years ago

10

The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Which

values of x hold true for the inequality?

1 answer:

OLga [1]3 years ago

7 0

3x+3>40, 3x > 37, x >37/3. It is not clear whether the numbers need be integers, so I leave the exact solution. No decimals neither.

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Answer:

The width W is :

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Step-by-step explanation:

<em>Let A be the area of the rectangle </em>

<em>Let L be the length of the rectangle</em>

<em>Let W be the width of the rectangle </em>

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Formula:

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$\begin{aligned}A &=L \times W \\\Rightarrow W &=\frac{A}{L} \\\Rightarrow W &=\frac{\frac{3}{8}}{\frac{5}{8}} \\&=\frac{3}{8} \times \frac{8}{5} \\&=\frac{3 \times 8}{8 \times 5} \\&=\frac{3}{5}\end{aligned}$

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3 years ago

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DochEvi [55]

Answer:

There is one solution

Step-by-step explanation:

2x + y = -1

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SIZIF [17.4K]

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2 years ago

Can someone help me on this

balandron [24]

Answer:

7

Step-by-step explanation:

→ Substitute x = -1 into - 5x + 2

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3 years ago