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Artist 52 [7]
3 years ago
12

Aluminum reacts with copper 2 chloride to make aluminum chloride and copper. Right the balanced equation

Chemistry
1 answer:
Ivan3 years ago
3 0

Answer:

2Al  + 3CuCl2 ---> 2AlCl3 + 3Cu

Explanation:

2Al  + 3CuCl2 ---> 2AlCl3 + 3Cu

You might be interested in
What is the vapor pressure of CS2CS2 in mmHgmmHg at 26.5 ∘C∘C? Carbon disulfide, CS2CS2, has PvapPvap = 100 mmHgmmHg at −−5.1 ∘C
Digiron [165]

Answer: 26.5 mm Hg

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at 26.5^oC = ?

P_2 = final pressure at -5.1^oC = 100 mm Hg

= enthalpy of vaporisation = 28.0 kJ/mol =28000 J/mol

R = gas constant = 8.314 J/mole.K

T_1= initial temperature = 26.5^oC=273+26.5=299.5K

T_2 = final temperature =-5.1^oC=273+(-5.1)=267.9K

Now put all the given values in this formula, we get

\log (\frac{P_1}{100})=\frac{28000}{2.303\times 8.314J/mole.K}[\frac{1}{299.5}-\frac{1}{267.9}]

\log  (\frac{P_1}{100})=-0.576

\frac{P_1}{100}=0.265

P_1=26.5mmHg

Thus the vapor pressure of CS_2CS_2 in mmHg at 26.5 ∘C is 26.5

7 0
3 years ago
26 grams of CO2 to moles
neonofarm [45]
First, find out how many grams are in one mole of CO2(the two oxygen atoms means you need to multiply oxygen’s amu by 2,then add whatever carbon’s amu is to that). Then divide 26 grams by that number and that will be your moles. There are only two significant figures, so round your answer correctly.
4 0
3 years ago
What is speed? If you walk 3 kilometers in 30 minutes, what is your average speed in kilometers per hour? Compare and contrast i
Mrrafil [7]

Answer:

See explanation

Explanation:

distance = 3 kilometres

time = 30 minutes or 0.5 hours

speed = distance/time = 3/0.5 = 6 Kmhr-1

Average speed is given by total distance covered divided by the total time taken while the instantaneous speed is the speed of an object at a particular instant or moment in time. Average speed refers to the whole journey while instantaneous speed refers to a particular point or instant in the journey.

distance= x

time = 3 hours

speed = 50 miles per hour

speed = distance/time

distance = speed * time

distance = 3 * 50

distance = 150 miles

3 0
2 years ago
How many liters of N2 are needed to react with 92 g of K, at STP, according to the following reaction? (Balance equation first.)
daser333 [38]
Sheeeeeeshhhhh uhh it’s carrot
6 0
2 years ago
Hcl and nh3 react to form a white solid, nh4cl. if cotton plugs saturated with aqueous solutions of each are placed at the ends
IgorLugansk [536]

24.4 cm.

<h3>Explanation</h3>

HCl and NH₃ reacts to form NH₄Cl immediately after coming into contact. Where NH₄Cl is found is the place the two gases ran into each other. To figure out where the two gases came into contact, you'll need to know how fast they move relative to each other.

The speed of a HCl or NH₃ molecule depends on its <em>kinetic energy</em>.

E_\text{k} = 1/2 \; m \cdot v^{2}

Where

  • E_\text{k} is the <em>kinetic energy</em> of the molecule,
  • m its mass, and
  • v^{2} the square of its speed.

Besides, the <em>kinetic theory</em> <em>of gases</em> suggests that for an ideal gas,

E_\text{k} \propto T

where \text{T} its temperature in degrees kelvins. The two quantities are directly proportional to each other. In other words, the <em>average kinetic energy</em> of molecules shall be the same for <em>any ideal gas </em>at the same<em> temperature</em>. So is the case for HCl and NH₃

E_\text{k} (\text{HCl}) = E_\text{k} (\text{NH}_3)

m(\text{HCl}) \cdot v^{2}(\text{HCl}) = E_\text{k} (\text{HCl}) = E_\text{k} (\text{NH}_3) = m(\text{NH}_3) \cdot v^{2}(\text{NH}_3)

Where

  • m(\text{HCl}), v(\text{HCl}), and E_\text{k}(\text{NH_3}) the mass, speed, and kinetic energy of an HCl molecule;
  • m(\text{NH}_3), v(\text{NH}_3), and E_\text{k}(\text{NH}_3) the mass, speed, and kinetic energy of a NH₃ molecule.

The ratio between the mass of an HCl molecule and a NH₃ molecule equals to the ratio between their <em>molar mass</em>. HCl has a molar mass of 35.45; NH₃ has a molar mass of 17.03. As a result, m(\text{HCl}) = 36.45 / 17.03 \; m(\text{NH}_3). Therefore:

36.45 /17.03\; m(\text{NH}_3) \cdot v^{2}(\text{HCl}) = m(\text{HCl}) \cdot v^{2}(\text{HCl}) = m(\text{NH}_3) \cdot v^{2}(\text{NH}_3)

36.45 /17.03\; v^{2}(\text{HCl}) = v^{2}(\text{NH}_3)

\sqrt{36.45 /17.03}\; v(\text{HCl}) = v(\text{NH}_3)

The <em>average </em>speed NH₃ molecules would be  \sqrt{36.45/17.03} \approx 1.463 <em>if</em>  the <em>average </em>speed of HCl molecules v(\text{HCl}) is 1.

\text{Time before the two gases meet} = \frac{\text{Length of the Tube}}{v(\text{HCl}) + v(\text{NH}_3)}

\text{Distance from the HCl end} = v(\text{HCl}) \times \text{Time before the two gases meet}\\\phantom{\text{Distance from the HCl end}} = v(\text{HCl}) \times \frac{ \text{Length of the Tube}}{v(\text{HCl}) + v(\text{NH}_3)}\\\phantom{\text{Distance from the HCl end}} = \frac{v(\text{HCl})}{v(\text{HCl}) + v(\text{NH}_3)} \times \text{Length of the Tube}\\\phantom{\text{Distance from the HCl end}} = \frac{1}{1 + 1.463} \times 60.0\; \text{cm} \\\phantom{\text{Distance from the HCl end}} = 24.4 \; \text{cm}

8 0
3 years ago
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