Answer:
Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...
Using an ionic chloride and Phosphoric acid
H3PO4 + NaCl ==> HCl + NaH2PO4
H3PO4 + NaI ==> HI + NaH2PO4
H2SO4 + NaCl ==> HCl + NaHSO4
This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.
The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.
2I-² === I2 + 2e-
Explanation:
[text]Solution:\\
Heat blance is gained by 50g =Heat balance lost by 25g of water\\
So,\\
\(M1 \times temp + M2 \times temp/M1+M2)\\\\\\\frac{(50.0g\times25.0^{.}c)+(23.0g\times57.0^{.}c)}{50.0g+23.0g} =35.1^{.}c}[/tex]
Answer:
148.2 g of H20
Explanation:
Equation of reaction: 4NH3 + 5O2 ---> 4NO + 6H20
From the equation above, 4 moles of ammonia reacts with 5 moles of oxygen gas to produce 6 moles water.
Molar mass of NH3 = 17 g/mol;
Molar mass of O2= 32 g/mol;
Molar mass of H2O = 18 g/mol
First, we determine the limiting reactant:
4*17 g of NH3 reacts with 5*32 g of O2
Mass Ratio = 68 : 160
Therefore, NH3 is the limiting reactant.
68 g of NH3 reacts to produce 6* 18 g of H20 = 108 g of H2O
93.3 g of NH3 will react to produce (93.3 * 108)/68 g of H20 = 148.2 g of H2O
Therefore, the maximum amount of H2O produced = 148.2 g
For a star to explode as a Type II supernova, it must be at several times more massive than the sun<span> (estimates run from eight to 15 solar masses). Like </span>the sun<span>, it will eventually run out of hydrogen and then helium fuel at its core. However, it will have enough mass and pressure to fuse carbon.
i had to right an essay on this stuff.</span>
