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patriot [66]
3 years ago
10

Calculate the molarity of a solution given the following information: 10g NaOH dissolved in 500 mL of solution.

Chemistry
2 answers:
MatroZZZ [7]3 years ago
7 0
First you calculate the number of moles of the solution :

Molar mass Of NaOH = 40.0 g/mol

number of moles = mass solute / molar mass

n = 10  / 40.0 

n = 0.25 moles of NaOH

Molarity  = number of moles / volume in liters

500 mL = 500 / 1000 = 0.5 L

M = 0.25 / 0,5

M = 0.5 M

Answer C

hope this helps!
Gelneren [198K]3 years ago
4 0
M= mol/L


10g NaOH x 1 mol / 40gNaOH = 0.25 mol NaOH

500mL / 1000 = 0.5 L


0.25 mol NaOH / 0.5 L = 0.5 M
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<h2>Explanations</h2>

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\begin{gathered} moles\text{ of KI}=\frac{mass\text{ of KI}}{molar\text{ mass of KI}} \\ moles\text{ of KI}=\frac{20g}{166g\text{/mol}} \\ moles\text{ of KI}=0.1205moles \end{gathered}

Since heat is lost, hence the enthalpy change of the solution will be negative that is:

\begin{gathered} \triangle H=-q \\ \triangle H=-(-1.045kJ) \\ \triangle H=1.045kJ \end{gathered}

Determine the enthalpy of solution in kJ•mol-1

\begin{gathered} \triangle H_{diss}=\frac{1.045kJ}{0.1205mole} \\ \triangle H_{diss}\approx8.67kJmol^{-1} \end{gathered}

Hence the enthalpy of solution in kJ•mol-1 for KI is 8.67kJ/mol

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1 year ago
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