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4 years ago

How to find the size of an angle

Mathematics

2 answers:

ikadub [295]4 years ago

8 0

Answer: Depends on the shape

Step-by-step explanation:

For example, the angle is 90 degrees

maksim [4K]4 years ago

3 0

Answer:

Well if the angle is drawn to scale you can use a protractor.

But if it’s not you need to divide the known length by the sine of its opposite angle.

So find the sine of the angle opposite to the known length.

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Which number when multiplied by 3 will result in a number smaller than 3?

MrRa [10]

Answer:

c bc c is a fraction which is smaller than a #

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3 years ago

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the area of a bathroom floor measures 2 yards by 3 yards and each custom tile that makes up the flooring is 1 1/2 square feet. h

katrin [286]

Multiply the 2 by 3 to get 6 square yards
Then multiply that by three to get 18 square feet
Finally times 18 by 1.5 to get 12 tiles

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4 years ago

PLEASE SOMEONE HELP ASAP!!!!!!!!!!!

Volgvan

The second and fourth one are rational. They are perfect squares and are terminating or are fractions

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3 years ago

Acellus

lisov135 [29]

Answer:

True

Step-by-step explanation:

90 degrees is a right angle

6 0

3 years ago

How does one integrate the following:

grin007 [14]

Consider substituting $u=4+xy$ , so that $\mathrm du=x\,\mathrm dy$ . Then

$\displaystyle\int_{x=a}^{x=b}\int_{y=a}^{y=b}\frac x{(4+xy)^2}\,\mathrm dy\,\mathrm dx=\int_{x=a}^{x=b}\int_{u=4+ax}^{u=4+bx}\frac1{u^2}\,\mathrm du\,\mathrm dx$
$=\displaystyle\int_{x=a}^{x=b}\left(-\frac1u\right)\bigg|_{u=4+ax}^{u=4+bx}\,\mathrm dx$
$=\displaystyle\int_{x=a}^{x=b}\left(\frac1{4+ax}-\frac1{4+bx}\right)\,\mathrm dx$

Then by similar substitutions, you can easily find that you end up with

$\dfrac1a\ln|4+ax|-\dfrac1b\ln|4+bx|\bigg|_{x=a}^{x=b}$
$=\dfrac1a\ln|4+ab|-\dfrac1b\ln|4+b^2|-\dfrac1a\ln|4+a^2|+\dfrac1b\ln|4+ab|$
$=\dfrac1a\ln\left|\dfrac{4+ab}{4+a^2}\right|+\dfrac1b\ln\left|\dfrac{4+ab}{4+b^2}\right|$

Of course, this all assumes that the integrand is continuous over the domain of integration, which would require that $a,b$ are chosen such that $xy\neq-4$ for any $(x,y)\in[a,b]^2$ . If in particular $ab>-4$ , then we can write

$=\dfrac1a\ln\dfrac{4+ab}{4+a^2}+\dfrac1b\ln\dfrac{4+ab}{4+b^2}$

and you can combine the logarithms if you like as

$=\ln\sqrt[a]{\dfrac{4+ab}{4+a^2}}+\ln\sqrt[b]{\dfrac{4+ab}{4+b^2}}$
$=\ln\left(\sqrt[a]{\dfrac{4+ab}{4+a^2}}\sqrt[b]{\dfrac{4+ab}{4+b^2}}\right)$

7 0

3 years ago