First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
The cost of each battery is .59
Step-by-step explanation:
Divide 4.72 by 8 to get the answer
Answer:100/9
Step-by-step explanation:
3 1/3 x 3 1/3
(3x3+1)/3 x (3x3+1)/3
10/3 x 10/3=100/9
2x²-10xy+3xy-15y²
Add like terms.
2x²+ (-10xy+3xy) -15y²
Simplify.
2x² + (-7xy) - 15y²
Rearrange the equation.
2x²-15y²-7xy
~Hope I helped~
Here you go. -1.5*(-8z)-(-1.5)(10)=
12z+15