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3 years ago

3 1/3 x 3 1/3 find the area of each square

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

3 0

Answer:100/9

Step-by-step explanation:

3 1/3 x 3 1/3

(3x3+1)/3 x (3x3+1)/3

10/3 x 10/3=100/9

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Amiraneli [1.4K]

$volume = \pi \times {r}^{2} \times h \\ volume = 3.142 \times (10 \div 2)^{2} \times 18 \\ volume \: = 3.142 \times 25 \times 18 \\ volume = 1413.9{cm}^{3}$

$price = \frac{1413.9 \times 0.02}{10} = 2.8278 = 2.83 \: dollars$

7 0

2 years ago

Read 2 more answers

Jim has $4,200 in his checking account to pay his rent. Each month, $600 is taken out of the account

Allushta [10]

Answer:4200-600m=1800

Step-by-step explanation:

4200-600m=1800

Subtract 4200 from 1800

-600m=-3600

Divide both sides by -600

m=6

5 0

3 years ago

I will give crown for answer

Romashka [77]

31 cups because 38 cups fit into 9 1/2 quarts so subtract 7 from 38 you get 31

6 0

3 years ago

A roof is shaped like a square pyramid. The base length is 10 meters and the slant height is 12 meters. What is the surface area

nasty-shy [4]

Surface area of square pyramid having square base side = 10 cm and slant height = 20 cm is 340 square meters

Solution:

Given that

Shape of the roof is square pyramid.

Base length of square pyramid roof = 10 meters

Slant height of square pyramid roof = 12 meters

Need to calculate the surface area of the roof

$\text { Surface area of square pyramid }=s^{2}+2 \times s \times l$

Where s is side of square base and l is slant height.

In our case s = 10 meters and l = 12 meters

On substituting the given values in formula we get

Surface area of square pyramid $=10^{2}+(2 \times 10 \times 12)=100+240=340 \text { meters }^{2}$

Hence surface area of square pyramid having square base side = 10 cm and slant height = 20 cm is 340 square meters.

6 0

3 years ago

A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is chang

zysi [14]

Answer:

The calculated z = 2.85 falls in the critical region z > 1.96 so we accept the null hypothesis that there is no difference between the population proportions for the two years.

Step-by-step explanation:

Let p1 be the sample of 1000 adults chosen in 2012 and

p2 be the sample of 1100 adults chosen in 2010

Part a:

The hypothesis that can be used to test for a significant difference between the population proportions for the two years is:

H0: p1-p2= 0 against the claim Ha: p1-p2≠0

Part b:

The sample proportion indicating that their financial security was more that fair in 2012 is

p1^= 410/1000= 0.41

In 2010 is:

p2^= 385/1100= 0.35

Part c:

p^c= 410+385/1000+1100= 0.3785

q^c= 1-p^c= 1-0.3785= 0.6124

The critical region is z > ±1.96

The test statistic is

z= p1^- p2^ / sqrt ( p^cq^c( 1/n1+ 1/n2)

z= 0.41-0.35 /sqrt( 0.3785*0.6124(1/1000 +1/1100)

z= 0.06 / 0.021036

z= 2.85

Conclusion

The calculated z = 2.85 falls in the critical region z > 1.96 so we accept the null hypothesis that there is no difference between the population proportions for the two years.

P- value : 0.00466

The result is significant( accept the null hypothesis) for value less than 0.05

Part d:

2012 2010

Sample 1000 1100

Proportions 0.41 0.35

Standard Error √0.41( 0.59)/1000 √0.35( 0.65)/1100

= 0.0155 0.01438

Standard Error for the difference = √0.0155² + 0.01438² =0.0211

p1-p2 ± z* standard error for the difference

0.41-0.35 ± 1.96 *( 0.0211)

0.06 ± 0.041356

-0.018644, 0.101356

The 95 % confidence interval estimate is (-0.018644, 0.10135

4 0

3 years ago