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3 years ago

3 1/3 x 3 1/3 find the area of each square

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

3 0

Answer:100/9

Step-by-step explanation:

3 1/3 x 3 1/3

(3x3+1)/3 x (3x3+1)/3

10/3 x 10/3=100/9

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HELP!!!!!! What is the equation of the axis of symmetry for the parabola

Dima020 [189]

Answer:

The line of symmetry is x = 3

Step-by-step explanation:

To find the line of symmetry in this case, use the base formula for vertex form.

y = a(x - h) + k

In this formula, h is the line of symmetry. In this case, h is 3.

3 0

3 years ago

What is the area<br> of the triangle?

elixir [45]

Area are all sides multiplied the formula can be found online

3 0

3 years ago

One of the legs of a right triangle measures 2 cm and its hypotenuse measures 19 cm.

pentagon [3]

Answer:

18.9

Step-by-step explanation:

361-4 = 357

the root of 357 is 18.9 when rounded

8 0

2 years ago

CALC- limits<br> please show your method

gladu [14]

A. Factor the numerator as a difference of squares:

$\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6$

c. As $x\to\infty$ , the contribution of the terms of degree less than 2 becomes negligible, which means we can write

$\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4$

e. Let's first rewrite the root terms with rational exponents:

$\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}$

Next we rationalize the numerator and denominator. We do so by recalling

$(a-b)(a+b)=a^2-b^2$
$(a-b)(a^2+ab+b^2)=a^3-b^3$

In particular,

$(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3$
$(x^{1/2}-x)(x^{1/2}+x)=x-x^2$

so we have

$\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}$

For $x\neq0$ and $x\neq1$ , we can simplify the first term:

$\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x$

So our limit becomes

$\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43$

3 0

3 years ago

A store sells pool floats.

Andrei [34K]

Step-by-step explanation:

the original retail price was 120% of the manufacturer price (100% manufacturer price + 20% markup).

now, the whole retail price is reduced by 12%.

that means we have to subtract 12% from the 120%.

but careful, we cannot just do 120-12=108.

that is simply because these 120% are now for this calculation the new basic amount and therefore 100%.

we actually need to calculate and subtract 12% of 120 to get the new percentage over the manufacturer price.

we do this by multiplying 120 by (100-12)/100 = 88/100 = 0.88 :

120 × 0.88 = 105.6%

so, the new retail price is now only 5.6% over the manufacturer price.

6 0

2 years ago