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3 years ago

Describe the electrodes in this iron-copper galvanic cell.

1 answer:

7 0

The anode is an electrode wherein the loss of mass takes place in composed of zinc while the cathode wherein it is the electrode that the gain of mass take place is composed of copper. By definition, a galvanic cell consists of redox processes wherein electrical is derived from it.

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Consider the decomposition of hydrogen peroxide reaction. If the rate of decomposition of hydrogen peroxide at a particular temp

Natasha2012 [34]

Answer:

0.049 mol/L.s

Explanation:

The decomposition of hydrogen peroxide is:

$H_2O_2 \to H_2O + \dfrac{1}{2}O_2$

$Rate = -\dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{\Delta [H_2O_2]}{\Delta t}= \dfrac{ 2 \Delta [H_2O_2]}{\Delta t}$

The rate of decomposition reaction = the rate of formation of $H_2O$ = 0.098 mol/L.s

∴

Rate of formation of $O_2$ $= \dfrac{ rate \ of \ reaction }{2}$

$= \dfrac{ 0.098 }{2}$

= 0.049 mol/L.s

8 0

3 years ago

Suppose that the mixture in problem 4 is at 15 OC, where the pure vapor pressures are 12.5 mmHg for water and 32.1 mmHg for etha

EleoNora [17]

Answer:

Explanation:

Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.

Using Raoult's Law:

$P_A = (P_o)_A*X_A$

For water:

$(P)w = P_o \times \text{mole fraction of water}$

where $P_o$ of water = 12.5 mmHg

Then, the vapor pressure of water:

$(P)w = 12.5 \ mmHg \times \text{mole fraction of water}$

For ethanol:

$P_E = P_o \times \text {mole fraction of ethanol}$

and the $P_o$ of ethanol = 32.1 mmHg

Then, the vapor pressure of ethanol:

$P_E = 32.1 \ mmHg \times \text {mole fraction of ethanol}$

The total vapor pressure $T_P = P_W + P_E$

The total vapor pressure = $(12.5 \ mmHg \times \text{mole fraction of water}) + (32.1 \ mmHg \times \text {mole fraction of ethanol})$

3 0

3 years ago

What is the molar mass of KOH?

Julli [10]

<h3>Answer:</h3>

56.11 g/mol

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Compound] KOH

<u>Step 2: Identify</u>

[PT] Molar Mass of K - 39.10 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

39.10 + 16.00 + 1.01 = 56.11 g/mol

5 0

3 years ago

What are two things affected by friction

11111nata11111 [884]

Answer:

speed and how slidey things are

Explanation:

4 0

3 years ago

In H2SO4, the oxidation number of H is , that of S is , and that of O is .

adell [148]

Answer:

Explanation:

A) In H2SO4, the oxidation number of H is , that of S is , and that of O is .

In H₂SO₄ the oxidation sate of H is +1 (H₂= +2) that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why two hydrogen atoms are attached with one SO₄ to balance the charge.

B) In CaSO4, the oxidation number of Ca is , that of S is . , and that of O is .

In CaSO₄ the oxidation sate of Ca is +2 that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why one calcium atoms is attached with one SO₄ to balance the charge.

C) In HF, the oxidation number of H is , and that of F is .

In HF the oxidation state of hydrogen is +1 and that of fluorine is -1. Both form ionic compound.

4 0

3 years ago