How many moles of Hydrogen gas will be produced if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid give
1 answer:
Taking into account the reaction stoichiometry, 1.25 grams of H₂ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
Mg + 2 HCl → MgCl₂ + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Mg: 1 mole
- HCl: 2 moles
- MgCl₂: 1 mole
- H₂: 1 mole
The following rule of three can be applied: if by reaction stoichiometry 2 moles of Mg form 1 mole of H₂, 2.5 moles of Mg form how many moles of H₂?
<u><em>moles of H₂= 1.25 moles</em></u>
Finally, 1.25 grams of H₂ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.
Learn more about the reaction stoichiometry:
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Answer:
a. HCl.
b. 0.057 g.
c. 1.69 g.
d. 77 %.
Explanation:
Hello!
In this case, since the reaction between magnesium and hydrochloric acid is:
Whereas there is 1:2 mole ratio between them.
a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:
Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.
b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:
c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:
Thus, the mass of excess magnesium turns out:
d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:
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