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Zinaida [17]
2 years ago
14

How many moles of Hydrogen gas will be produced if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid give

n the following balanced chemical reaction:
Mg + 2HCl → MgCl2 + H2

Group of answer choices

A. 1.25 moles

B. 5.0 Moles

C. 7.5 moles

D. 2.5 moles
Chemistry
1 answer:
nadezda [96]2 years ago
7 0

Taking into account the reaction stoichiometry, 1.25 grams of H₂ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg + 2 HCl  → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg: 1 mole
  • HCl: 2 moles
  • MgCl₂: 1 mole
  • H₂: 1 mole

<h3>Mass of hydrogen formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 2 moles of Mg form 1 mole of H₂, 2.5 moles of Mg form how many moles of H₂?

moles of H_{2} =\frac{2.5 moles of Mgx1 mole of H_{2} }{2 moles of Mg}

<u><em>moles of H₂= 1.25 moles</em></u>

Finally, 1.25 grams of H₂ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

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Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = \frac{5.50 g}{90 g/mol}=0.06111 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}

The molarity of the solution :

=\frac{0.06111 mol}{0.09766  L}=0.6257M

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

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Calculate the pH of the solutions: [H^+]= 1.6 x 10^-3 M
Yuliya22 [10]

Answer:

A) pH = 2.8

B) pH = 5.5

C) pH = 8.9

D) pH = 13.72

Explanation:

a) [H⁺]  = 1.6 × 10⁻³ M

pH = -log [H⁺]

pH = -log [1.6 × 10⁻³ ]

pH = 2.8

b) [H⁺]  = 3 × 10⁻⁶

pH = -log [H⁺]

pH = -log [3 × 10⁻⁶ ]

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c) [OH⁻] = 8.2 × 10⁻⁶

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pOH = 5.1

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