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LenKa [72]
3 years ago
10

You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles​ [mol] of 40 grams

​ [g] of this compound. The compound has the​ formula: Upper X 5 Upper Y 7 Upper Z 6​, where the components are​ X, amuequals50​; ​Y, amuequals45​; ​Z, amuequals10.
Chemistry
1 answer:
Serhud [2]3 years ago
6 0

Answer : The moles of given compound is, 0.064 mole

Explanation : Given,

Mass of given compound = 40 g

Atomic mass of X = 50 amu

Atomic mass of Y = 45 amu

Atomic mass of Z = 10 amu

First we have to calculate the molar mass of given compound.

The given compound formula is, X_5Y_7Z_6

Molar mass of X_5Y_7Z_6 = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)

Molar mass of X_5Y_7Z_6 = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol

Now we have to calculate the moles of given compound.

\text{Moles of given compound}=\frac{\text{Mass of given compound}}{\text{Molar mass of given compound}}

\text{Moles of given compound}=\frac{40g}{625g/mol}

\text{Moles of given compound}=0.064mol

Thus, the moles of given compound is, 0.064 mole

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yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of N_2 = 8.00 atm

The partial pressure of O_2 = 5.00 atm

K_p = 0.0025

The balanced equilibrium reaction is,

                               N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initial pressure     8.00      5.00            0

At eqm.               (8.00-x) (5.00-x)        2x

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}

Now put all the values in this expression, we get :

0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}

By solving the terms, we get:

x=0.15atm

The equilibrium partial pressure of N_2 = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of N_2 is 7.8 atm.

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3 years ago
What is the average mass of a single sulfur atom in grams?
Nostrana [21]
32.066 atomic mass units.
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A resource is being used by a population.
jonny [76]

Answer:

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Explanation:

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It represents a constant function

5 0
1 year ago
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Marat540 [252]

Answer:

The correct option is <em>A) The light moths will be captured by predators more easily than the dark moths, and the population of dark moths will rise.</em>

Explanation:

As we can see, the colour of the trees do not match with the light moths. Instead, the colour of the trees resembles the dark moths. This adaptation will work best for the dark moths to protect it from its predators. The light moths lack this adaptation and can easily be attacked  by the predators. Hence, the population of the dark moth will increase as they are better adapted to live in such an environment.

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3 years ago
At 9°C a gas has a volume of 6.17 L. What is its volume when the gas is at standard temperature?
Alex17521 [72]

Answer:

V₂ = 5.97 L

Explanation:

Given data:

Initial temperature = 9°C (9+273 = 282 K)

Initial volume of gas  = 6.17 L

Final volume of gas = ?

Final temperature = standard = 273 K

Solution:

Formula:

The Charles Law will be apply to solve the given problem.

According to this law, 'the volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure'

Mathematical expression:

V₁/T₁ = V₂/T₂

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T₁ = Initial temperature

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T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 6.17 L ×  273K /  282  k

V₂ = 1684.41 L.K / 282 K

V₂ = 5.97 L

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