<span>pOH = 9.2
pH = 4.8</span><span>
That's your </span>answer!!
Hope I helped!! :)
I believe it is <span>d. the bonds of both the reactants and the products are formed.</span>
Answer:
The answer to your question is 71.22 g
Explanation:
Data
Density = 19.3 g/cm³
Volume = 0.00369
mass = ?
Formula
Density = 
Solve for mass
mass = density x volume
Process
1.- Convert volume from liters to cubic centimeters
1 l ---------------- 1000 cm³
0.00369l --------- x
x = (0.00369 x 1000 ) / 1
x = 3.69 cm³
2.- Substitution
mass = 19.3 x 3.69
3.- Simplification and result
mass = 71.22 g
835 g Ar to liters of Argon gas is calculated as follows
find the moles of Ar = mass/molar mass
= 835g /39.95 g/mol = 20.9 moles
At STP 1mole of ideal gas = 22.4 L, what about 20.9 moles
= 20.9 moles/1mole x 22.4 L =468.16 L of Argon