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Ne4ueva [31]
3 years ago
15

Andrew drives through 5 intersections with stoplights on his way to work. He records that he is stopped by a red light in 2 of t

he 5 intersections. If he uses this as his general probability of getting stopped at a red light on his way to or from work, how many times can he expect to be stopped at a red light over the next 40 times he drives through an intersection on his route? Andrew should expect to be stopped times.
Mathematics
1 answer:
photoshop1234 [79]3 years ago
4 0

Answer:

He should expect to be stopped a total of 16 times

Step-by-step explanation:

What the question is saying is that out of every 5 intersections, he would be stopped at 2.

Now, for forty times in which he passes through an intersection , we want to know the number of times in which he would be stopped

In this case we only need to multiply the probability by the number of times in which he passes an intersection and that would be 2/5 * 40 = 16 times

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miss Akunina [59]

Answer:

I can help with Q "4" as -

It uses triangle congruence test -  here we use - SAS, as

one side is equal as it is given

both the  angles are 90 degree

and they share a same side

so -

8x = 6x + 5

8x - 6x = 5

2x = 5

x = 2.5

RU = 6x+ 5 = 6 (2.5) + 5 = 20

( I am not so sure but I think this is the answer )

3 0
3 years ago
Please help me with this math question!
nlexa [21]
If the temperature drops 35 degrees everyday for 7 days, you would have to add -35 + -35 + -35 +-35 + -35 + -35 + -35, since each day it drops the temperature would be -35, now the answer would be -245.

Hopefully this helped. :)
8 0
3 years ago
Read 2 more answers
What is the value of A when we rewrite 1.44^1.2x as A^x​
Lina20 [59]

Answer:

a = 0.64

Step-by-step explanation:

hope that helped

3 0
2 years ago
2.5(t - 2) - 6 = 9 (solve for the unknown variable)
Elis [28]

2.5(t - 2) - 6 = 9

2.5(t - 2) = 9 + 6 = 15

t - 2 = 15/2.5 = 150/25 = 6

t = 6 + 2 = 8

Answer: 8

Check: 2.5(8 - 2) - 6 = 2.5(6) - 6 = 1.5(6) = 9  good


3 0
3 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
3 years ago
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