A rectangle has a perimeter of 60 inches and length of 22 what is the width of the rectangle
1 answer:
perimeter = 2l +2w
length = 22
perimeter = 60
60 = 2(22) +2w
60 = 44 +2w
subtract 44 from both sides
16 = 2w
w = 16/2
w = 8
width is 8 inches
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The polygon would have 18 sides. Hope this helps!
6*5=30
8*2=16
30+16=46
The test was worth 46 total points
Answer:
10+20x-12
20x-2
X=20-2
X=18
D. 118 would be the answer
