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stepan [7]
3 years ago
14

A rectangle has a perimeter of 60 inches and length of 22 what is the width of the rectangle

Mathematics
1 answer:
Phoenix [80]3 years ago
6 0

perimeter = 2l +2w

length = 22

perimeter = 60

 60 = 2(22) +2w

60 = 44 +2w

 subtract 44 from both sides

16 = 2w

w = 16/2

w = 8

 width is 8 inches


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A box of cashews peanuts and almonds contains 270 nuts. for every 5 cashews there are 6 peanuts and 7 almonds. How many more are
yKpoI14uk [10]
For every 5 cashews, there are 6 peanuts and 7 almonds.

Means:    Cashews:Peanuts:Almonds = 5:6:7

Sum of ratio = 5 + 6 +7 = 18

Cashews =    (5/18) * 270 = 75


Peanuts =    (6/18) * 270 = 90


Almonds =    (7/18) * 270 = 105

So how many more what are there than peanuts?

The number of that nuts Minus the number of peanuts.

= Number of that nuts  -  90
5 0
3 years ago
Find the area of a sector of a circle with radius 6 centimetre if angle of sector is 60 degree​
Gnesinka [82]

Answer:

Step-by-step explanation:

area=\frac{\pi r^2 \times\theta}{360} =\frac{\pi 6^2 \times 60}{360} =6 \pi \approx 18.85~ cm^2

6 0
3 years ago
Please answer this question now
vichka [17]

Answer:

320 sq in

Step-by-step explanation:

4(1/2*8*16) + (8*8)

= 4(64) + (64)

= 5(64)

= 320

6 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
Of the 600 sixth graders at Melville Middle School, 80% want more field trips. How many students want more field trips? Use the
irga5000 [103]

Answer:

480 students want more field trips.

60 students is 10%.

Step-by-step explanation:

There are 600 students, and 80% want more field trips.

80% of 600 is 0.8*600 = 8*60 = 480 students.

480 students want more field trips.

6 0
3 years ago
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