All categories

3 years ago

HELPPP PLEASE i need a fast reply asking for a friend in need of desperate help :((((

Mathematics

1 answer:

weqwewe [10]3 years ago

8 0

Answer:

y =14

11x = 11*3.5 =38.5

3x+2y = 11x = 38.5

Step-by-step explanation:

The perimeter of a triangle is the sum of all three sides

3x+2y + 11x+y = 91

Combine like terms

14x +3y = 91

The lines mean the sides are equal

3x+2y = 11x

Simplify

Subtract 3x from each side

3x-3x+2y = 11x-3x

2y = 8x

Divide by 2

2y/2 = 8x/2

y = 4x

Substitute 4x in the first equation every time you see y

14x +3y = 91

14x +3(4x) = 91

14x+12x=91

26x = 91

Divide by 26

26x/26 =91/26

x = 3.5

Now we can find y

y = 4x

y = 4(3.5)

y = 14

We know x and y we can find the length of each of the sides

y =14

11x = 11*3.5 =38.5

3x+2y = 11x = 38.5

You might be interested in

Convert the decimal number to the base stated<br><br> 113 to base 6

Oduvanchick [21]

Answer:

the answer is 341(I think)

4 0

3 years ago

Read 2 more answers

A bacteria colony is quickly growing in a petri dish. The number of bacteria, y , is modeled by the function y=2(10)^2 where x i

koban [17]

Answer:

C = 159600

Step-by-step explanation:

Because its Y=2 (10) square so times by its self.

7 0

4 years ago

Musya8 [376]

Answer:

No, this is not a right triangle.

4 0

3 years ago

True or false: is a rectangular also a square

IRISSAK [1]

I do not believe so, because a square is in the rectangle family. If a rectangle was in the square family, it would have to have all sides the same length, wich wouldnt make it a rectangle anymore.

5 0

3 years ago

PLEASE HELP

Anit [1.1K]

Answer:

$A\approx2.255 \text{ grams}$

Step-by-step explanation:

We will use the standard formula for half-life:

$\displaystyle A=A_0(a)^\frac{t}{d}$

Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.

So, we will substitute 1/2 for a and 24.3 for d. This yields:

$\displaystyle A=A_0(\frac{1}{2})^\frac{t}{24.3}$

We have a 3 gram sample. Therefore, our initial amount A₀ is 3:

$\displaystyle A=(3)(\frac{1}{2})^\frac{t}{24.3}$

And we want to find the remaining sample after 10 days. So, t=10. Substitute:

$\displaystyle A=(3)(\frac{1}{2})^\frac{10}{24.3}$

Use a calculator. So:

$A\approx2.255 \text{ grams}$

Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.

6 0

3 years ago