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Alex777 [14]
3 years ago
9

Why is it difficult to grow anaerobes in vitro?

Biology
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

 Anaerobes are not able to have growth in the presence of much of oxygen environment as they do not have catalse .Catalse is the enzyme for clearance of oxygen.There are also anaerobes protects their own self from oxygen by production of an enzyme known as super oxide dismutase. Therefore, it is not easy task for creation an oxygen-absent environment for anaerobes in the vitro so they cannot be grown in vitro.

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Cyanobacteria can make their own food because they contain what
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Cyanobacteria can make their own food because they contain chlorophyll. 
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Which of the following is true of microbes?A. Ninety-nine percent of all microbes are pathogenic.B. Gene expression in bacteria
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B. Gene expression is in them is similar to us but facilitates the use of bacteria in recombiant biotechnology and gene therapy.
We human have eukaryotic cells which have a devoloped nucleas whereas small bacteria have prokaryotic cells with no definite nucleus using more biotechnology. Other all are not true.
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4 years ago
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A scientist finds a new life form and determines that it contains no nuclei. Which of the 6 kingdoms could it belong to? Select
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Answer: The correct answer is -

Eubacteria and Archaebacteria.

As per the information in the question, scientist finds a new life form and determines that it contains no nuclei.

This indicates that the new life form is a prokaryote.

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Archaebacteria (primitive forms of bacteria) and Eubacteria are the two groups of prokaryotes.

Thus, Eubacteria and Archaebacteria is the right answer.

8 0
3 years ago
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A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V'  = ρ'V" - ρV"

(ρ - ρ")V'  = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

5 0
3 years ago
What are the phenotypes of an organism?
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Answer:

A.

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