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Natali [406]
3 years ago
15

Assign True to the variable has_dups if the string s1 has any duplicate character (that is if any character appears more than on

ce) and False otherwise.
Computers and Technology
1 answer:
podryga [215]3 years ago
4 0

Answer:

#include <iostream>

using namespace std;

int main()

{

   string s;

   cin>>s;    //reading string

   int i,j;

   bool has_dups=false;

   int n= s.length();

   for(i=0;i<n;i++)  //to check for duplicate characters

   {

       for(j=0;j<n;j++)

       {

           if(j!=i && s[i]==s[j])  //to check if it is matched with itself

           {

               has_dups=true;  //if true no need to check others

               break;

           }

       }

   }

   cout<<has_dups;

   return 0;

}

OUTPUT :

California

1

Explanation:

Above program finds if a character repeat itself in the string entered by user.

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Consider the formula: G=D+(A+C^2)*E/(D+B)^3 Show the order that a processor would follow to calculate G. To do so, break down th
motikmotik

Answer:

1. G=D+(A+C^2)*E/(D+B)^3

cobegin:

p1: (D+B)

p2: p1^3

p3: C^2

p4: A+ p3

p5: E/p2

p6: p4 * p5

p7: D + p6

   :G

coend

2. Now The value A=2, B=4, C=5, D=6, and E=8

p1: 6+4 =10

p2: p1 ^3= 10^3= 1000

p3: c^2= 5^2 =25

p4: A + p3= 2 +25 =27

p5: 8/1000

p6: 27 *8/1000

p7: D+ P6= 6+ 216/1000

      = 6216/1000

      =6.216

Explanation:

The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.

4 0
3 years ago
Your database was damaged due to hardware failure. What can you use to restore it?
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The intended purpose of the following module is to determine whether the value parameter is within a specified range. The module
BARSIC [14]

The program does not consists of any syntax error but the module contains error in logic especially while placing the condition inside if statement.

Here we are actually planning to check whether the number passed in the “value” variable is within the given lower and upper range which is passed in second and third parameter.

Solution 1:

if value<=lower AND value>=upper Then

Display “The given number is outside the specified range.”

else

Display “The given number is within the specified range.”

End if

Alternate solution:

So for that the condition needs to be value>=lower and value <=lower. so  

if value > lower AND value <upper Then

Display “The given number is within the specified range.”

else  

Display “The given number is within the specified range.”

7 0
4 years ago
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