As we look, line TU = 16. But, there are two lines right below it, and there are two lines on the line UW. Now, all that this means is UW is the same length as TU.
Since we know what TU and UW is and we need to add them together to find the total length of the line TW.
16 + 16 = 32.
Therefore, the length of line TW is 32 units long.
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The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,
Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96.
Answer: x=4
Step-by-step explanation:
The refrection of a point or set of points across the line y = x will result in a point or set of points whose coordinates are the interchange of the x-value and the y-value of the original point or set of points.
Given that the vertices of a triangle are P(-8, 6), Q(1, -3) and R(-6, -3), the vertices of the triangle formed by the refrection Ry=x<span>(ΔPQR) are P'(6, -8), Q'(-3, 1) and R'(-3, -6).</span>