Answer: mx+2ny+z −zy4−zx3 4xy3x4y−5x
Step-by-step explanation:
there u go
Answer:
The jetski is 2.28 dB loud when the person is 41 feet away.
Step-by-step explanation:
Loudness (L) ∝ 1 / Distance² (d²)
Introduce a constant 'K'
L = K (1/d²)
L = K/d²
K = Ld²
Find the K from a previously known information: If a person 8 feet from a jetski hears 60 decibels loud
∴ d = 8 ft , L = 60 db
K = 60(8²) = <em>3840</em>
How loud is the jetski when the person is 41 feet away?
Distance is now 41 ft
since: L = K/d²
∴ L = 3840 / 41²
L = 3840 / 1681
L = 2.28 db
Given :
New York City has a population of 8.55 million and 300 square mile area .
Manhattan has 1.64 million and 23 square miles area .
To Find :
How much greater is the population density of Manhattan than New York City.
Solution :
Population density of New York City :
Now ,
Therefore , population density of Manhattan is 
greater than New York City .
Hence , this is the required solution .
First we will divide. Lets do it:-
1152 ÷ 2 = 576.
Now we will check our work:-
576 × 2 = 1152.
So, the quotient 1152 as an equation is:- 1152 ÷ 2 = ?.
Hope I helped ya!!
Answer:
i need more info or i cannot help
