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3 years ago

How do you cut a right triangle to make 1 pentagon and 2 triangles

Mathematics

2 answers:

Tanya [424]3 years ago

7 0

Cut only to ends of the triangle off then it will have a pentagon with the uncut shape

tresset_1 [31]3 years ago

7 0

Cut a pentagon out of the triangle and 2 small triangles will b left

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Given: p(a) =0.70, p(b)=0.60, p(a or b) =0.88. are a and b independent? (use your answer from question

allsm [11]

Answer:

Step-by-step explanation:

P(a or b) = P(a) + P(b) - P(a and b)

0.88 = 0.70 + 0.60 - P(a and b)

P(a and b) = 1.30 - 0.88 = 0.42.

So the events a and b are not mutually exclusive.

4 0

2 years ago

A cube has a lateral area of 676 square feet.<br> What is the side length of the cube?

sp2606 [1]

Answer:

13 ft.

Step-by-step explanation:

Lateral Surface area of a cube is the area of 4 sides, front side, back side, left side face and right side face.

It can be seen seen from the attached figure as well.

Each face in a cube is a square. And each side in the cube is equal.

So, Lateral surface area is nothing but 4 $\times$ area of a square.

And we know that area of a square = $side^{2}$ .

Hence, Lateral surface area = $4 \times side^{2}$

As per question:

$4 \times side^{2}$ = 676

$side^2 = 169 \\\Rightarrow side = 13$

Hence, side length of cube = 13 feet.

7 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

*PLEASE ANSWER, DIFFICULT QUESTION ASAP* A particular airline offers three free snack options to it's passengers: cookies, chips

Svet_ta [14]

The answer would be 50% because you have the choice two options

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3 years ago

Suppose that every day from Monday through Friday,

snow_tiger [21]

Answer: You take around 4,500 steps a day

Step-by-step explanation:

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3 years ago