Since a^2 - b^2 = 1, the value of y = 1 because x=1 and 1^2 - 1^2 = 0
11 is closest but i realy think 11.3 is closest if thats an answer
The value of d which will.make this system have the same solution is; d = 21/(3x -1)
First, we must make y, the subject of the formula in each case as follows;
- y = (3x -1)/7. and
- y = 3/d.
In essence, by equating y to y in both equations; we have;
By Cross-product; we have;
Read more on subject of formula;
brainly.com/question/11000305
You need the odd integers to be separated by 2. One will not work.
If n is odd, n + 1 will be even. You cannot get an exception to that. Try it.
1 is odd but 1 + 1 is even.
n and n + 3 produces 1 odd and 1 even. If n is odd then since 3 is odd when the two are added together, you get an even. Again try it
n = 5
n + 3 = 8
C: is not the answer.
D can't work either. If n is odd then n + 2 will be odd but n + 1 is even.
The Answer is B.
n(n + 2) = 195
n^2 + 2n - 195 = 0
(n - 13)(n + 15)
n can be 13 and n + 2 can be 15
13 * 15 = 195
But here's something you may not know
n can be - 15 and then the other odd number would be - 13
