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3 years ago

An equation for the opposite of -12

Mathematics

1 answer:

Crank3 years ago

7 0

Answer: (positive) 12

Step-by-step explanation:

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The equation y = –x + 4 is the boundary line for the inequality y < –x + 4. Which sentence describes the graph of the inequal

Sladkaya [172]

I think the answer is B The region shaded below a solid boundary line. I'm only 75% sure

8 0

3 years ago

Read 2 more answers

Is the function continuous at x = -17

Pavlova-9 [17]

For a function to be continuous at an x-value, say -17, you need to make sure two things line up:

The limit from the left equals the limit from the right.

$\lim_{x \to -17^{-}} f(x) = \lim_{x \to -17^{+}} f(x)$

This limit equals the functions value.

$\lim_{x \to -17} f(x) = f(-17)$

The left hand limit involves the first piece, f(x) = 20x + 1:

$\begin{aligned} \lim_{x \to -17^{-}} f(x) &= \lim_{x \to -17^{-}} (20x+1)\\[0.5em]&= 20(-17)+1\\[0.5em]&= -339\endaligned}$

The right hand limit invovles the second piece, f(x) = -10x^2:

$\begin{aligned} \lim_{x \to -17^{+}} f(x) &= \lim_{x \to -17^{+}} (-10x^2)\\[0.5em]&= -10\cdot (-17)^2\\[0.5em]&= -2890\endaligned}$

Since the two one-sided limits don't match, the function is not continuous at x=-17.

3 0

3 years ago

Donna bought 5 bags of dog treats for $14.00. What is the cost per bag of dog treats?

Alex17521 [72]

Answer:

2.8

Step-by-step explanation:

14 divided by 5=2.8

Hope this helps you! <3

6 0

3 years ago

Read 2 more answers

If you can help me that would be great the instructions are to factor these polynomial Don’t answer just to get pointsNO LINKS!!

natima [27]

Answer:

3. 3(x+y)(x-y)

4. (y²+4)(y+2)(y-2)

5. 2(3x+1)(x+2)

Step-by-Step:

3. 3(x²-y²) = 3(x+y)(x-y)

4. y⁴-16 = (y²+4)(y²-4)= (y²+4)(y+2)(y-2)

5. 6x²+14x+4 = 2(3x²+7x+2) = 2(3x+1)(x+2)

PLEASE RATE!!! I hope this helps!!!

If you have any question comment below

(I have verified my answers on an online calculator)

4 0

2 years ago

How do you this question (pre-cal)

Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into $\csc^2( B )$

One way we can do that is through the following steps:

$\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\$

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

4 0

3 years ago