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nikdorinn [45]
3 years ago
15

How do you determine the quadratic equation having roots that are real numbers and equal​

Mathematics
2 answers:
zvonat [6]3 years ago
6 0

Answer:

To determine the nature of roots of quadratic equations (in the form ax^2 + bx +c=0) , we need to calculate the discriminant, which is b^2 - 4 a c. When discriminant is greater than zero, the roots are unequal and real. When discriminant is equal to zero, the roots are equal and real.

daser333 [38]3 years ago
5 0

ANSWER:

when the value of (b^2-4ac) is positive, then the roots are real and distinct.

when it is 0 the roots are equal and if it is negative than its root is not real.

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Solve pls brainliest
Goshia [24]

Hey there!

39 = - u / 6

MULTIPLY 6 to BOTH SIDES

39(9) = (-u / 6)(6)

CANCEL out: the RIGHT side

KEEP: the LEFT side because it helps solve for the u-value

NEW EQUATION: -u = 234

DIVIDE -1 to BOTH SIDES

-1u / -1 = 234 / -1

CANCEL out: -1 / -1 because it gives you 1

KEEP: 234 / -1 because it gives you the result of the u-value

NEW EQUATION: u = 234 / -1

SIMPLIFY IT!

u = -234

Therefore, your answer is: [u = -234]

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 0
3 years ago
Read 2 more answers
Which expression shows the result of applying the distributive property to 9(2+5m) ?
vovikov84 [41]

Answer:

<h2>18 + 45m</h2>

Step-by-step explanation:

The distributive property: a(b + c) = ab + ac

9(2 + 5m) = (9)(2) + (9)(5m) = 18 + 45m

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3 years ago
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Step-by-step explanation: it just is

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x-60 is the length. Multiply you get x2-110x=3000 this is a quadratic equation.

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