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3 years ago

How do you determine the quadratic equation having roots that are real numbers and equal

Mathematics

2 answers:

zvonat [6]3 years ago

6 0

Answer:

To determine the nature of roots of quadratic equations (in the form ax^2 + bx +c=0) , we need to calculate the discriminant, which is b^2 - 4 a c. When discriminant is greater than zero, the roots are unequal and real. When discriminant is equal to zero, the roots are equal and real.

daser333 [38]3 years ago

5 0

ANSWER:

when the value of (b^2-4ac) is positive, then the roots are real and distinct.

when it is 0 the roots are equal and if it is negative than its root is not real.

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You are hiking and are trying to determine how far away the nearest cabin is, which happens to be due north from your current po

Margaret [11]

Answer:

336.7 yards away from the cabin....

Step-by-step explanation:

The angle 30.7° is also the angle of the upper interior angle of the triangle (near the cabin)

Use the tan function:

opposite = 200 yards

adjacent = x

tan(30.7°) = (opposite / adjacent)

tan(30.7°) = 200 yards/x

x * tan(30.7°) = 200 yards

x = 200 yards/ tan(30.7°)

x= 200/ 0.594

x = 336.7 yards.

336.7 yards away from the cabin....

8 0

3 years ago

When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode

yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are central tendency measures in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a normal distribution, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a distribution is not symmetrical, we say it is skewed. The skewness is a measure of the asymmetry of the distribution. In this case, the mean, median and mode are not the same, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (negative skew), or greater than them (positive skew), or approximately equal than the median but much greater than the mode (a variation of a positive skew case).

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a mound-shaped symmetrical distribution, it resembles the normal distribution and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, they are all approximately equal. So, the general relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, considering they have similar characteristics of the normal distribution, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0

3 years ago

What two numbers add to get 4 and multiply to get -4

SIZIF [17.4K]

-2 and -2 Two negatives added equal a positive.............. . . .. . . . . . .

6 0

3 years ago

To find the product of 42.12 and 10³, move the decimal point in 42.12 __ places to the right because 10³ has __ zeros.

Yakvenalex [24]

<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>

Solution:

Given that,

$\text{ product of } 42.12 \text{ and } 10^3$

Which means,

$42.12 \times 10^3$

Here, the exponent of 10 is positive ( which is 3)

When the exponent is positive, we have to move the decimal point to right

When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10

Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12

Therefore,

$42.12 \times 10^3 = 42120$