Answer: pOH = 3.13
Ba(OH)2 is a very basic substance. The general formula for pOH is - log(OH)
Barium Hydroxide produces 2 moles of OH for every mole of Ba(OH)2 present in the solution.
0.00037 M = 3.7 * 10^-4 Ba(OH)2 will produce 2 *0.00037 M of OH-
OH- = 2* 0.00037 = 0.00074
pOH = - log(0.00074) = 3.13
The ans should be C. ( if i'm not wrong )
This is because the solubility of oxygen increases when temperature in the water is cooler. Cold water can hold more dissolved oxygen than warm water, thus having a higher concentration of oxygen.
The answer is strontium dihydrogen phosphate
That is strontium dihydrogen phosphate, is the compound containing the most hydrogen atoms per molecule or formula unit.
The formulas of the following compounds are as follows:
Hydrogen selenide H₂Se
Ammonium bromide NH₃Br
Strontium dihydrogen phosphate Sr(H₂PO4)₂
Sodium bicarbonate NaHCO₃
As it can be seen from the formula of strontium dihydrogen phosphate Sr(H₂PO4)₂
, that it contains the most hydrogen atoms per molecule or formula unit.
Based on the concentrations given, the volume of vinegar required is 5.04 mL.
<h3>What is the concentration of the vinegar solution?</h3>
The concentration of a solution is the amount of solute in a given volume of solution.
Concentration can be expressed as:
- molar concentration
- percentage concentration
The concentration of the vinegar solution is 4.76% (w/w). This means that 4.76 g of vinegar is present in 100 g of solution.
Mass of vinegar = 4.76 g
molar mass if vinegar = 60 g/mol
moles of vinegar = 4.76/60 = 0.0793 moles
volume of solution/water = 100 mL or 0.1 L
Molarity of vinegar = 0.0793/0.1 = 0.793 M
1 mole of vinegar reacts with 1 mole of NaOH
let the volume of vinegar required be V
0.793 M × V = 40 × 0.1
V = 4/0.793
V = 5.04 mL
Therefore, the volume of vinegar require is 5.04 mL.
Learn more about molarity at: brainly.com/question/26528084
