What is the reaction that corresponds to the first ionization energy of rubidium, rb?

1 answer:

6 0

Ionization is a process in which an electron present in the outermost orbital of an atom gets knocked out by absorbing an appropriate amount of energy. Release of electron from a neutral atom results in the formation of a cation- a positively charged ion.

Rubidium (Rb) is an alkali metal with a valence electron configuration of 5s¹. Ionization results in the loss of this '5s' electron forming a Rb+ ion. The reaction can be expressed as:

Rb (5s¹) → Rb⁺ (5s⁰) + e⁻

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The formula for a compound of Li+ ions and Br- ions is written LiBr. Why can’t it be written Li2Br? Why isn’t it written BrLi?

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Lithium has charge of +1 and bromide has charge of - 1. So they combine to form the compound lithium bromide which is expressed as LiBr.

<h3>Explanation:</h3>

Lithium is an alkali metal placed in group 1 or periodic table. It has a valency of 1 which is achieved as lithium loses an electron to achieve a charge of +1.

Bromine is a halogen which is placed in group 17 of periodic table. It has a valency of 1 which is achieved as bromine looses an election to achieve a charge of - 1.

Lithium is the cation and bromide is the anion. So lithium is written in front and bromine following the cation. And as both of their valencies are 1, so they form the compound LiBr.

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