The rate of Formation of Carbocation mainly depends on two factors'
1) Stability of Carbocation: The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.
2) Ease of detaching of Leaving Group: The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,
R-I > R-Cl > R-F
B > C > A
You can cross multiply, it will be easy
Answer:
i think it's B maybe..I'm not sure
The element X is Copper.
Explanation :
Reactive metals from 3d transition series like Cu are very reactive because their standard reduction potential values are low.
Hence, when treated with a acid it tends to liberate hydrogen gas.
Also, because of its low reduction potential value, it can easily displace lead and tin from their salt solutions.
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