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4 years ago

Find f(-2). (I have the answer, I just don’t know how to do it)

Mathematics

1 answer:

34kurt4 years ago

3 0

Answer:

You plug in -2 into where it says x, then you solve.

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Find the nth term<br><br> 1, 5, 9. 13, 17

mojhsa [17]

a1 = 1 and d = 4

a(n) = a1 + d(n - 1)

a(n) = 1 + 4(n - 1)

8 0

3 years ago

I need a bit of help on this one: mr. james borrows money from the bank to buy a new car. he borrows 10,000 at 3% for 5 years. H

EastWind [94]

Answer:

Between $11,000-$11,500

Between $10,500-$11,000

Between $9,500-$10,000

Between $9,000-$9,500

Between $10,000-$10,500

Correct answer:

Between $10,000-$10,500

8 0

3 years ago

Please help I’ll mark you as brainliest if correct

laila [671]

Answer:

the answer is A. because a 1/2 inch is 2 feet there is about 2 and 1/2 of an inch so if you add that, that will be 9 feet

Step-by-step explanation:

6 0

3 years ago

Please answer this I have trouble with it

Strike441 [17]

For the 1 first problem you have to do additive inverse where the subtraction sign is and then combine all the z's and then combine the normal numbers and then put plus sign in between

8 0

3 years ago

Read 2 more answers

18,000 amounts to 21,600 in 4 years at simple interest. Find the sum of

AnnyKZ [126]

Answer:

$\$20,400$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

step 1

Find the rate of interest

in this problem we have

$t=4\ years\\ P=\$18,000\\ A=\$21,600\\r=?$

substitute in the formula above and solve for r

$\$21,600=\$18,000(1+4r)$

$1.2=(1+4r)$

$4r=1.2-1$

$r=0.2/4=0.05$

The rate of interest is $5\%$

step 2

Find the sum of money that will amount to 25,500 in 5 years, at the same rate of interest

in this part we have

$t=5\ years\\ P=?\\ A=\$25,500\\r=0.05$

substitute in the formula above and solve for P

$\$25,500=P(1+0.05*5)$

$P=\$25,500/(1.25)=\$20,400$

3 0

3 years ago