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Arturiano [62]
4 years ago
5

A checking account has the following balances:

Mathematics
1 answer:
ASHA 777 [7]4 years ago
3 0

Answer:

The true balance is $562.43

Step-by-step explanation:

1. Check register balance of $459.70

2. Bank statement balance of $562.43

3. Two outstanding checks of $76.40 and $29.83

4. Service charge of $3.50.

The working is shown like -

Subtract the service charge from check register balance

459.70-3.50=456.20 dollars

Then add the outstanding checks to this

456.20+76.40+29.83=562.43 dollars

Hence, the true balance is $562.43.

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Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c
Elina [12.6K]

Answer:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

Step-by-step explanation:

Data given

n_1 =8 represent the sample size for group Boston

n_2 =9 represent the sample size for group Dallas

\bar X_1 =47 represent the sample mean for the group Boston

\bar X_2 =44 represent the sample mean for the group Dallas

s_1=3 represent the sample standard deviation for group Boston

s_2=3 represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

\sigma^2_1 =\sigma^2_2 =\sigma^2

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

The statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t student distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

Replacing we got:

\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9

And the deviation would be just the square root of the variance:

S_p=3

The statitsic would be:

t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058

The degrees of freedom are:

df=8+9-2=15

And the p value would be:

p_v =P(t_{15}>2.058) =0.0287

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are significantly higher than those in Dallas

5 0
4 years ago
What is the equation of the described circle? A) (x − 2)2 + (y + 3)2 = 58 B) (x − 2)2 + (y + 3)2 = 68 Eliminate C) (x + 2)2 + (y
SIZIF [17.4K]

Answer:

Step-by-step explanation:

64

8 0
4 years ago
You start with one robot. Each moment this robot can either self-destruct, do nothing, make one copy of itself, or make two copi
IgorLugansk [536]
So there are 4 choices
1 destroys itself
1 does nothing
1 coppies itself
1 makes 2 coppies of itself

so 1 in  4 that is destroys itself in the first time
1 in 4 that is basically skips this turn
1 in 4 that is doubles itself
1 in 4 that you will have 3 robots

we can count the skip turn as nothing so
1 in 4 that is is destroyed
2 in 4 or 1/2 that is does not destory itself
so if it doubled itself, this makes it more complicated
if it tripples itself, this makes if even more complicate
not exactly sure what the correct answer is
4 0
3 years ago
The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2
mario62 [17]

The two equation which can be used to solve the problem are:

5n - 3d = 0 and 3n - 2d = -2

<h3><u>Solution:</u></h3>

The numerator of the fraction is "n" and the denominator of the fractions is "d"

<em><u>The numerator and denominator of a fraction are in the ratio of 3 to 5</u></em>

numerator : denominator = 3 : 5

\frac{numerator}{denominator} = \frac{3}{5}

\frac{n}{d} = \frac{3}{5}

On cross-multiplication we get,

5n = 3d

<h3>5n - 3d = 0</h3>

This is our first equation

The numerator and denominator are both increased by 2, the fraction is now equal to 2/3

The new numerator will be n + 2 and denominator will be d + 2

\frac{n + 2}{d + 2} = \frac{2}{3}

On cross multiplication we get,

3(n + 2) = 2(d + 2)

3n + 6 = 2d + 4

<h3>3n - 2d = -2</h3>

This is our second equation

Thus the two equation which can be used to solve the problem are:

5n - 3d = 0 and 3n - 2d = -2

7 0
3 years ago
6p=0.6(5p+15) in two ways please
Len [333]
Does that make sense?? Or do u need more ??

4 0
4 years ago
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