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garri49 [273]
3 years ago
13

Ok this has nothing to so with my assignments or anything but i have a serious question please help so my question is....

Mathematics
1 answer:
umka2103 [35]3 years ago
5 0
If she is stated in the will she can. If not, then she can't unless You simply give it to her once you inherit the money.
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If a coin is tossed 5 times, what is the probability that it will land heads each time
Sever21 [200]
1/2 because there are only two sides heads and tails. applies to each time you toss the coin
4 0
3 years ago
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Simplify: 5y-3/12y - y-5/20y:<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5y-3%7D%7B12y%7D%20-%5Cfrac%7By-5%7D%7B20y%7D"
Damm [24]

Answer:

i think the answer is -y^2/20 + 2y/3 - 1/4

6 0
3 years ago
1. Which of the following is an arithmetic sequence?
Ronch [10]

i say C. -5, -2, 1, 4, 7 is your answer for question 1.

and for question 2 i think is E. -6, -4, -2, 0, 2.

7 0
3 years ago
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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
Viktor [21]

Answer:

<h2> (2, -1)</h2>

Step-by-step explanation:

Given the function f(x) = 8x³ − 12x² − 48x, <em>the critical point of the function occurs at its turning point i,e at f'(x) = 0</em>

First we have to differentiate the function as shown;

f'(x)= 3(8)x^{3-1}- 2(12)x^{2-1} - 48x^{1-1}\\  \\f'(x) = 24x^2 - 24x-48x^0\\\\f'(x) = 24x^2 - 24x-48\\\\At \ the\turning\ point\ f'(x)= 0\\24x^2 - 24x-48 = 0\\\\\\

Dividing \ through \ by \ 24\\\\x^2-x-2 = 0\\\\On \ factorizing\\\\x^2-2x+x-2 = 0\\\\x(x-2)+1(x-2) = 0\\\\(x-2)(x+1) = 0\\\\x-2 = 0 \ and \ x+1 = 0\\\\x = 2 \ and \ -1

Hence the critical numbers of the function are (2, -1)

8 0
3 years ago
which of the following best describes 4^2/3? a. sq root of 16, b. cube root of 4, c. sq root of four, d. cube root of 16
son4ous [18]

Answer: D) cube root of 16

================================================

Explanation:

The rule we use is

x^{m/n} = \sqrt[n]{x^m}

In this case, x = 4, m = 2 and n = 3.

So,

x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\

Showing that the original expression turns into the cube root of 16.

4 0
3 years ago
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