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seraphim [82]
3 years ago
7

a man is four times as old as his son in five years time he will be three times as old as his son what is the present age of the

son in years​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

I would start by setting up a chart like I did below.

Label one column age now and the other age in 5 years.

Since we don't know the son's age we use x.

We do know that the man's age is 4 times the son's age.

So the man's age will be 4x.

In the age in 5 year column, we add 5 to their current ages.

Now set up our equation.

Since it says "in five years" we use information in second column.

In 5 years time, he, "4x + 5", will be, equals,

3 times as old as his son, "3(x + 5)".

So we have 4x + 5 = 3(x + 5).

Solving from here, we find that x = 10.

So the son is 10 and the man is 4 times his age or 40.

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Let f(X)=3√x
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g(x) = 3√(x-5) -1

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Horizontal stretching: It means the graph is elongated or shrink in x direction.

Vertical stretching : It means the graph is elongated or shrink in y direction

Vertical translation : It means moving the base of the graph in y direction

Horizontal translation : It means moving the base of the graph in x direction

According to rules of transformation f(x)+c shift c units up and f(x)-c shift c units down.

Therefore, in order to  move the graph down 1 units, we need to subtract given function by 1 , we get

g(x) = 3√x -1

According to rules of transformation f(x+c) shift c units left and f(x-c ) shift c units right.

Therefore, in order to  move the graph left by 5 units, we need to add given function by 5 , we get

g(x) = 3√(x-5) -1

To learn more about graphical transformation,  refer to brainly.com/question/4025726

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On a single roll of a pair of dice, what are the odds against rolling a sum of 12?
o-na [289]

Answer:

\frac{1}{35}

Step-by-step explanation:

On a single roll of a pair of dice. When a pair of dice are rolled the possible outcomes are as follows:

(1,1)         (1,2)          (1,3)  (1,4)  (1,5)  (1,6)

(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)

(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6)

The number of outcomes that gives us 12 are (6,6). There is only one outcome that gives us sum 12.

Total outcomes = 36

Odd against favor = \frac{non \ favorable\ outcomes}{favorable \ outcomes}

Number of outcomes of getting sum 12 is 1

Number of outcomes of not getting sum 12 is 36-1= 35

odds against rolling a sum of 12= \frac{1}{35}

3 0
3 years ago
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