Answer:
6.2 seconds
Explanation:
Using Newton's second law, ∑F=ma, we know the net force acting on the object is Force applied-Force of friction. The net force is 203 N. Newton's second law requires the mass of an object, not the weight force, so we will have to calculate the mass. We know that m*g=weight force, in this case, solve for the mass and you will get 210 kg. Now that we have the value of the net force and the mass, we can solve for acceleration. =0.967 m/s^2. Now, since we have the acceleration, initial velocity(0 m/s), and the final velocity (6m/s) we will use these to solve for time using the kinematic equation Vf=Vi + at. Plug in the values we know and solve for time and you will get 6.2 seconds
By definition we have to:
Applied force: It is the external force that acts directly on a body.
Therefore, we can say that if you have an object and push it towards yourself, you are exerting an external force on the object.
This external force was not acting on the object previously, therefore, it is a force that you are applying at that moment.
Answer:
you exert an Applied Force on an object when you pull it towards you
A. Applied Force
Umm....."the following"? what do u mean? i can help u, but i need full question to do so.
Since the electrons and neutrino are emitted at rigt angles, the nucleus is emitted at opposite side to right angle. So Pe , Pnue and Pnu are the momentum vectors.
Then Pnu^2 = Pe^2 + Pnue^2 => (9.80 âś• 10-23)^2 + (5.70 âś• 10-23)^2
Pnu^2 = 128.53 x 10^-46
Pnu = 1.13 x 10^-22 kg-m/s
The momentum is in quadrant 3 along positive x axis with angle of direction = 180 + arctan (Pnue/Pe) = 180 + 30 (approx) = 210 degrees