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Romashka-Z-Leto [24]
3 years ago
10

Find your mass if a scale on earth reads 650 N when you stand on it.

Physics
1 answer:
netineya [11]3 years ago
7 0

Weight = (mass) x (gravity)

Acceleration of gravity on Earth = 9.8 m/s²

                                           Weight on Earth = (mass) x (9.8 m/s²)

Divide each side by  (9.8 m/s²):          Mass = (weight) / (9.8 m/s²)

                                                            Mass = (650 N) / (9.8 m/s²)

                                                           Mass = 66.33 kg  (rounded)
 
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When the wedges are removed, the cars will move. Predict which direction they will move and when they will stop
Neko [114]

Answer: hello your question lacks the required diagram attached below is the required diagram

answer : Both cars will move backwards and stop due to friction.

Explanation:

Given that both cars are negatively charged, When the wedges are removed both cars will move backwards ( repelling each other ) because they are like poles, and Like poles repel each other. while unlike poles attract each other ( forward movement )  .

The cars will later come to a stop due to frictional forces between the cars and the surface.

6 0
3 years ago
Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.
andriy [413]

Answer:

K = ρL²g

Explanation:

Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;

Then:

F = upthrust ( restoring force) = weight of the liquid displaced.

F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g

where;

A = L²

\rho_{\omega} = \rho

F = ky.

Then,

Ay \rho g = ky

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K = ρL²g

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3 years ago
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5 0
2 years ago
A wheel rotates about a fixed axis with an initial angular velocity of 13 rad/s. During a 8-s interval the angular velocity incr
____ [38]

Answer:

The number of revolutions is 44.6.

Explanation:

We can find the revolutions of the wheel with the following equation:

\theta = \omega_{0}t + \frac{1}{2}\alpha t^{2}

Where:

\omega_{0}: is the initial angular velocity = 13 rad/s              

t: is the time = 8 s

α: is the angular acceleration

We can find the angular acceleration with the initial and final angular velocities:

\omega_{f} = \omega_{0} + \alpha t

Where:

\omega_{f}: is the final angular velocity = 57 rad/s

\alpha = \frac{\omega_{f} - \omega_{0}}{t} = \frac{57 rad/s - 13 rad/s}{8 s} = 5.5 rad/s^{2}

Hence, the number of revolutions is:

\theta = \omega_{0}t + \frac{1}{2}\alpha t^{2} = 13 rad/s*8 s + \frac{1}{2}*5.5 rad/s^{2}*(8 s)^{2} = 280 rad*\frac{1 rev}{2\pi rad} = 44.6 rev

Therefore, the number of revolutions is 44.6.

       

I hope it helps you!

4 0
2 years ago
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