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Ivenika [448]
3 years ago
15

Write a quadratic equation in standard form with roots -2 and -5

Mathematics
1 answer:
patriot [66]3 years ago
7 0
To solve this problem. First lets work our way backwards and try to figure out the binomials that will result in these roots.

-2 root = X int = -2
Thus it would be (X +2) because if you solve for x the solution or X intercept is -2.
Same thing for -5.
(X+5).

Next place them together and multiply or foil to obtain the quadratic.

Y = (X+5)(X+2)
Y = X^2 + 7x + 10

Standard form = Ax^2 +/- Bx +/- C = 0.

The standard form is X^2 + 7x + 10.
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The yellow boxes on the bottom are the answers. Please help TYSM
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Answer:

1.\ 8p = 64, p =8

2. -\dfrac{w}{4} = 8, w = -32

3. -5c = -20, c =4

4.\ 9m=45, m = 5

5. \dfrac{b}{25} = -3, b =-75

6. \dfrac{d}{-2} = 20, d=-40

Step-by-step explanation:

Now let us see the detailed solution of each part:

Part 1:

8p -15 = 49\\\Rightarrow 8p =49+15\\\Rightarrow  8p = 64\\\Rightarrow p =8

Part 2:

\dfrac{-w}{4}+18=26\\\Rightarrow \dfrac{-w}{4} = 26-18\\\Rightarrow \dfrac{-w}{4} = 8\\\Rightarrow -w = 8 \times 4\\\Rightarrow w =-32

Part 3:

-5c-15=-35\\\Rightarrow -5c = -35 +15\\\Rightarrow -5c = -20\\\Rightarrow c = 4

Part 4:

9m +10=55\\\Rightarrow 9m =55-10\\\Rightarrow 9m =45\\\Rightarrow m =5

Part 5:

\dfrac{b}{25}-83=-86\\\Rightarrow \dfrac{b}{25} = -86 +83\\\Rightarrow \dfrac{b}{25} = -3\\\Rightarrow b = -75

Part 6:

\dfrac{d}{-2}+85=105\\\Rightarrow \dfrac{d}{-2} = 105-85\\\Rightarrow \dfrac{d}{-2} = 20\\\Rightarrow d=20 \times -2\\\Rightarrow d =-40

Please refer to attached image for the answers.

7 0
3 years ago
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