Write a quadratic equation in standard form with roots -2 and -5
1 answer:
To solve this problem. First lets work our way backwards and try to figure out the binomials that will result in these roots.
-2 root = X int = -2
Thus it would be (X +2) because if you solve for x the solution or X intercept is -2.
Same thing for -5.
(X+5).
Next place them together and multiply or foil to obtain the quadratic.
Y = (X+5)(X+2)
Y = X^2 + 7x + 10
Standard form = Ax^2 +/- Bx +/- C = 0.
The standard form is X^2 + 7x + 10.
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Step-by-step explanation:
Answer:
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The measure of angle theta is 30 degrees.
This is a 30-60-90 triangle where the short leg is half that of the hypotenuse. The short leg is opposite the smallest angle 30 degrees.
You can use trig to find that
sin(angle) = opposite/hypotenuse
sin(theta) = 5/10
sin(theta) = 0.5
theta = arcsin(0.5)
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Answer:
1e+30
Step-by-step explanation:
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