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Kitty [74]
3 years ago
9

3 3/5 - 1 1/2 help plz

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0
The answer would be 21/10 or in mixed form 2 1/10

3 3/5- 1 1/2

Subtract the whole numbers and factional parts of the mixed number separately

(3-1)+(3/5- 1/2)

Subtract the numbers

2+ 1/10

Write as a mixed fraction or faction

2 1/10 or 21/10
Gwar [14]3 years ago
5 0

Answer:

21/10

Step-by-step explanation:

3 3/5= 18/5

1 1/2 = 3/2

18/5=36/10

3/2 = 15/10

(36-15)/10 = 21/10

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victus00 [196]

Answer:

320/4=8   8 tens /4 tens =2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Answer please thanks
Leto [7]

Answer:

(2A /h) - b1 = b2

Step-by-step explanation:

A = 1/2 h ( b1 + b2)

Multiply each side by 2

2A = 2*1/2 h ( b1 + b2)

2A =  h ( b1 + b2)

Divide each side by h

2A/h= h/h ( b1 + b2)

2A/h=  b1 + b2

Subtract b1 from each side

2A /h - b1 = b2

3 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
If you flip three fair coins, what is the probability that you’ll get heads on the first two flips and tails on the last flip
Len [333]

Answer:

1/8

Step-by-step explanation:

5 0
3 years ago
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OLEGan [10]
I got C b I’m not 100% sure
7 0
3 years ago
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