A student solved this problem and said the answer was 3 feet.

Mathematics

1 answer:

Anastaziya [24]2 years ago

4 0

The answer is B the answer is not reasonable it should be about 1 foot hope i can help

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Set up a right triangle model for this problem and solve by using the reference table trigonometric ratio that applies. Follow t

RSB [31]

In reference to the angle of elevation (41 degrees), the adjacent side is 60 and the opposite side is the unknown.
Using tangent ratio:
tan 41 = opp/60
60 tan41 = opp
opp side = 52.2yards
LETTER B

5 0

2 years ago

Read 2 more answers

Simplify n^6 × n^5 × n^4 ÷ n^2 ÷ n<br>PLEASE ANSWER ASAPPP!!! Will get BRAINLIEST****

babymother [125]

Answer:

n¹³

Step-by-step explanation:

Division and multiplication have the same priority in pemdas, so you can solve this by dividing/multiplying from left to right.

Also remember that when dividing exponents of the same base, you subtract them, and when multiplying, you add them.

n⁶· n⁵ · n⁴ ÷ n³ · n² ÷ n

= (n⁶· n⁵) · n⁴ ÷ n³ · n² ÷ n

= (n¹¹ · n⁴) ÷ n³ · n² ÷ n

= (n¹⁵ ÷ n³) · n² ÷ n

= (n¹² · n²) ÷ n

= n¹⁴ ÷ n

= n¹³

Ultimately you just have to calculate

6 + 5 + 4 - 3 + 2 - 1 = 13

6 0

2 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$