Question

Please help with this

Answer 1

Answer:

33

Step-by-step explanation:

$a+b+c=-3,\ x+y=-9\qquad(*)\\\\-2c-2a-3y-2b-3x=-2a-2b-2c-3x-3y\\\\=-2(a+b+c)-3(x+y)\\\\\text{from}\ (*)\ \text{we have}\\\\=-2(-3)-3(-9)=6+27=33$

Answer 2

Answer:

33

Step-by-step explanation:

a+b+c = -3

x+y = -9

Multiply the first equation by -2

-2(a+b+c )= -3*-2

-2a+-2b+-2c = 6

Multiply the second equation by -3

-3 (x+y) = -9*-3

-3x -3y = 27

Add the two equations together

-2a+-2b+-2c = 6

-3x -3y = 27

---------------------

-2a -2b-2c-3x-3y = 6+27

Rearranging the order

-2c-2a-3y-2b-3x = 33