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allsm [11]
3 years ago
10

I'LL GIVE U BRAINLY IF U ANSWER CORRECTLY Willie runs 5 miles in 20 minutes. If Willie runs at the same rate, how many miles can

he run in 28 minutes?
Mathematics
2 answers:
Greeley [361]3 years ago
7 0
Willie will run seven miles in 28 minutes. I think I’m right!(:
elena55 [62]3 years ago
6 0

Answer:

Willie will run 7 miles in 28 minutes.

Step-by-step explanation:

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joja [24]
1. x=6
2. y=6
3. x=10
4. y=10

1.c+9= 19
2. 9-y=7
3. 5y=30
4. u-u=0

1. 2(3x2 - 5x3)
   2(6-15)
   2x(-9)=18

3 0
3 years ago
Please help! I will give Brainliest!<br> Who is correct?
soldi70 [24.7K]

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Step-by-step explanation:

8 0
3 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
How do I find the answer?
grin007 [14]

Answer:

Step-by-step explanation:

87*

3 0
2 years ago
polygon B is a scaled copy of polygon A using a scaled factor of 5. polygon A's area is what fraction of polygon B's area
marishachu [46]

Answer:

1/5

Step-by-step explanation:

polygon B's area is 5 times greater than polygon A

3 0
3 years ago
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