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2 years ago

Isn’t 3 to the -2 power 9 right?

Mathematics

1 answer:

DaniilM [7]2 years ago

8 0

Answer: No

Step-by-step explanation: If you mean 3^-2 it would be 0.111111111 repeating. 3^2 is 9 not -2

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7x(x+4) 7x^2+4 7x^2+28x 8x+4 8x+11

Scilla [17]

Answer:

$7x^2+28x$

Step-by-step explanation:

$7x(x+4)\\\\Multiplication\ is\ distributive\ on\ addition\\\\\Rightarrow 7x(x+4)=7(x\times x+x\times 4)\\\\7x(x+4)=7(x^2+4x)\\\\Multiplication\ is\ distributive\ on\ addition\\\\\Rightarrow 7x(x+4)==7\times x^2+7\times 4x\\\\7x(x+4)=7x^2+28x$

6 0

3 years ago

What is the answer to the problem above in the picture

lana66690 [7]

Answer: Third option.

Step-by-step explanation:

Some transformations for a function f(x) are shown below:

If $f(x)+k$ , the function is translated "k" units up

If $f(x)-k$ , the function is translated "k" units down.

If $f(x+k)$ , the function is translated "k" units left.

If $f(x-k)$ , the function is translated "k" units right.

In this case you have the following function:

$f(x)=3x+2$

And you know that the function g(x) is obtained by translating the function f(x) 5 units down and 3 units left; therefore, you can conclude that g(x) is:

$g(x)=3(x+3)-3$

Finally, simplifying, you get that this is:

$g(x)=3x+9-3\\\\g(x)=3x+6$

5 0

3 years ago

How do you do question b?

notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

$\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\$

-----------------

This means,

$\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\$

is the solution with the initial condition y(0) = 0.

6 0

3 years ago

The midpoint of RS¯¯¯¯¯¯¯ is M. Use the given endpoint R(23, 14) and midpoint M(13, 8) to find the coordinates of the other endp

Oksanka [162]

The coordinates of other endpoint S is (3, 2)

<h3>Solution:</h3>

Given that midpoint of RS is M

Given endpoint R(23, 14) and midpoint M(13, 8)

To find: coordinates of the other endpoint S

The formula for midpoint is given as:

For a line containing containing two points $(x_1, y_1)$ and $(x_2, y_2)$ midpoint is given as:

$m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here in this problem,

m(x, y) = (13, 8)

$(x_1, y_1) = (23, 14)\\\\(x_2, y_2) = ?$

Substituting the given values in above formula, we get

$(13,8)=\left(\frac{23+x_{2}}{2}, \frac{14+y_{2}}{2}\right)$

Comparing both the sides we get,

$\begin{aligned}&13=\frac{23+x_{2}}{2} \text { and } 8=\frac{14+y_{2}}{2}\\\\&26=23+x_{2} \text { and } 16=14+y_{2}\\\\&x_{2}=3 \text { and } y_{2}=2\end{aligned}$

Thus the coordinates of other endpoint S is (3, 2)

8 0

3 years ago

I need to solve 5y+1<36

bezimeni [28]

Answer:

y<7 since if you subtract 1 from both sides and then divide both sides by 5 you get y<7

7 0

3 years ago