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larisa [96]
3 years ago
6

A) What is the meaning of specific heat capacity ?​

Physics
1 answer:
dem82 [27]3 years ago
3 0

Explanation:

the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

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A penny is dropped from the top of a building that is 300.0 m tall. Calculate the speed of the penny as it hits the ground. (met
Sauron [17]

We have the equation of motion s = ut + \frac{1}{2} at^2, where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here s = 300 m, u = 0 m/s, a = 9.81 m/s^2

Substituting

   300 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2 = 300\\ \\ t =7.82 seconds

Now we have v = u+at, where v is the final velocity

Here u = 0 m/s, a= 9.81 m/s^2 and t = 7.82 seconds

Substituting

     v = 0+9.8*7.82 = 76.68 m/s

The speed with which the penny strikes the ground = 76.68 m/s.

3 0
3 years ago
If HST has a tangential speed of 7,750 m/s, how long is HST’s orbital period? The radius of Earth is 6.38 × 106 m. s
Sladkaya [172]
 the orbital period is 5170 s
6 0
3 years ago
a 3,000kg truck runs into the rear of a 1000kg car that was stationary. The truck and car are locked together after the collisio
joja [24]
FVJDJFN.s<ldF KN,M c":F,BJ TNHIJRT IHJYODIFG 
7 0
3 years ago
S A voltage ΔV is applied to a series configuration of n resistors, each of resistance R. The circuit components are reconnected
Flura [38]

The power of is series combination is Vn^2 times that of a parallel combination.

For series combination :

Req = R + R + R + ............... n times = nR

I = Δv/nr

Power = (Δv/nr)^2 × nr = Δv^2/nr

For parallel combination

1/req = 1/R + 1/R + 1/R +................(n times) = n/R

Req = R/n

Power = Δv/(R/n) = nΔv^2/R

Ratio = Δv^2/nr/n·Δv^2/R = 1/n^2

Hence, power of is series combination is Vn^2 times that of a parallel.

Learn more about parallel combination here:

brainly.com/question/12400458

#SPJ4

3 0
2 years ago
In February 1955, a paratrooper fell 365 m from an airplane without being able to open his chute but happened to land in snow, s
DaniilM [7]

Answer:

a. i=4760 kg*m/s

b. D_U= 1.11 m

Explanation:

a)

F= 120,000N

Kinetic energy @ impact = 120,000*depth

K_E= (1/2)*85kg*(56m/s)^2

K_E=133280 J

D_U= \frac{133280J}{120000N} = 1.11 m

b)

The momentum is equal to the impulse on him from the snow so:

p=m*v

p=85kg*56m/s

i=4760 kg*m/s

7 0
3 years ago
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