D. Your mass and the mass of the planet
Answer:
The surface tension of plain water can cause a needle to float.
Evidently, the addition of detergent to the water reduces the surface tension of the liquid causing the needle to sink.
Answer:
1.65 m
Explanation:
Energy from spring,
is given by
where k is spring constant and x is the compression distance


Kinetic energy, KE at the highest point is given by
where m is mass and v is velocity
KE=0.5*0.0227*2.27= 0.058485 J
Potential energy, PE of spring is given by
PE=mgh where g is gravitational constant and h is maximum height reached by the mouse
PE=0.0227*9.81= 0.222687h
According to the principle of conservation of energy, the potential energy of the compressed spring is equal to the potential and kinetic energy of the mouse at the maximum high point.

0.425=0.222687h+0.058485
h=(0.425-0.058485)/ 0.222687=1.646671 m
h=1.65 m
Yes. This is indeed the location of an object.
Explanation:
It is given that,
Separation between the charges, r₁ = 2 m
Force between the charges, F₁ = 20 N
Separation between the charges finally, r₂ = 4 m
Let F₂ is the repulsive force. The formula for the repulsive force is given by :






So, the repulsive force is 5 newton. Hence, this is the required solution.