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harina [27]
2 years ago
12

Define a combination circuit.

Physics
1 answer:
Neporo4naja [7]2 years ago
7 0

Answer:

a circuit that is a blend of series paths and parallel paths. See Figure for a visual explanation. Most circuits are of this variety. Don't be afraid to tackle these circuits as far as the math goes.

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State advantages of ultrasonic sound in determining the depth of the ocean ​
agasfer [191]

Answer:

It has <u>greater accuracy than other nondestructive methods in determining the depth of internal flaws and the thickness of parts with parallel surfaces.</u>

Explanation:

Hope this helps you!

5 0
2 years ago
A spectroscope prism separates the white light from a star into a very wide spectrum. When widely spread, black lines appear in
topjm [15]

Answer:

C. It helps scientists detect dark matter.

Explanation:

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5 0
2 years ago
Read 2 more answers
A wildebeest and chicken participate in a race over a 2.00km long course. the wildebeest travels at a speed of 16.0m/s and chick
Nezavi [6.7K]

Answer:

(a)  The distance of the chicken from the finish line is 62.5 m

(b) The stationary time of the wildebeest is 675 s

Explanation:

Given;

total distance traveled by wildebeest and chicken, d = 2 km = 2000 m

speed of the wildebeest, v_w = 16 m/s

speed of the chicken, v_c = 2.5 m/s

Time for wildebeest to finish the race without stopping, 2000 / 16 = 125 s

Time for chicken to finish the race without stopping, 2000/2.5 = 800 s

(b) for how long in time (in s) was the wildebeest stationary?

t(stationary) = t(chicken) - t(wildebeest)

t = 800s - 125 s

t = 675 s

(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?

The time taken for the wildebeest to run 1.6 km (1600 m) is given by;

t = 1600 / 16 = 100 s

The total time spent by the wildebeest before it resumed the race = stationary time + 100s

t (total) = 675 s + 100 s = 775 s

Distnace traveled by the chicken when the wildebeest resumed the race = 2.5m/s x 775s = 1937.5 m

Thus, the distance of the chicken from the finish line = 2000 m -  1937.5 m

the distance of the chicken from the finish line = 62.5 m

7 0
3 years ago
football player A has a mass of 110 kg is running on the field is velocity of 2 m/s football player B has a mass of 120 kg and a
valkas [14]

Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

<u>Given the following data;</u>

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

a. To find the momentum of A;

Momentum \; A = 110 * 2

Momentum A = 220 Kgm/s.

b. To find the momentum of B;

Momentum \; B = 120 * 0

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

Total \; momentum = Momentum \; A + Momentum \; B

Substituting into the equation, we have;

Total \; momentum = 220 + 0

<em>Total momentum = 220 Kgm/s. </em>

7 0
3 years ago
Water is discharged from a pipeline at a velocity v (in ft/sec) given by v = 1306p(1/2), where p is the pressure (in psi). If th
shepuryov [24]

Answer:

a=38.5 ft/sec^{2}

Explanation:

Note that acceleration is the rate change of velocity i.e

acceleration=\frac{change in velocity}{change in time}\\a=\frac{dv}{dt} \\.

Since the velocity is giving as a variable dependent on the pressure, we have to differentiate implicitly both side with respect to time,i.e

\frac{dv}{dt}=1306*(1/2)p^{-1/2}\frac{dp}{dt} \\

if we substitute value for the pressure as giving in the question and also since the rate change of pressure is 0.354psi/sec, we have

a=653*0.1667*0.354\\

a=\frac{dv}{dt}=653(36)^{-1/2}*0.354\\  a=38.5 ft/sec^{2}

3 0
2 years ago
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