I think it's 6/8, you multiply by 2. 3/4 x 2 = 6/8.
Answer:
d = 120 [m]
Explanation:
In order to solve this problem, we must use the theorem of work and energy conservation. Where the energy in the final state (when the skater stops) is equal to the sum of the mechanical energy in the initial state plus the work done on the skater in the initial state.
The mechanical energy is equal to the sum of the potential energy plus the kinetic energy. As the track is horizontal there is no unevenness, in this way, there is no potential energy.
E₁ + W₁₋₂ = E₂
where:
E₁ = mechanical energy in the initial state [J] (units of Joules)
W₁₋₂ = work done between the states 1 and 2 [J]
E₂ = mechanical energy in the final state = 0
E₁ = Ek = kinetic energy [J]
E₁ = 0.5*m*v²
where:
m = mass = 60 [kg]
v = initial velocity = 12 [m/s]
Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.
W₁₋₂ = -f*d
where:
f = friction force = 36 [N]
d = distance [m]
Now we have:
0.5*m*v² - (f*d) = 0
0.5*60*(12)² - (36*d) = 0
4320 = 36*d
d = 120 [m]
3 tonnes
The answer is 3 tonnes, because 3 tonnes equal 6613.87 pounds, which is higher than 6001.
I hope this helps! I would love it if you could help me answer my question too!
Answer:489 Revolutions
Explanation:
Given
Angular deceleration
Given wheel angular velocity =96 rad/s when machine is turned off
time taken by machine to reach zero angular velocity
0=96+(-1.5)t
t=64 sec
angular displacement is given by
For revolutions =
At the instant you dropped it from your hand, its speed was zero.
The coin gained 9.8 m/s every second it fell. At the end of 1.85 sec,
just before it went 'tink' onto the ground, its speed was
(9.8 m/s) x (1.85 sec) = 18.13 m/s .
Its velocity at that final instant was 18.13 m/s downward.
