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Gala2k [10]
2 years ago
5

Fig. 9.1

Physics
1 answer:
larisa [96]2 years ago
5 0

Answer:

Okay let say from the diagram you have more force come in from the B point of the magnet and release out from A point of the magnet. so lets say north is always the attractive spot and south is your releasing spot.

Explanation:

meaning from magnet the north pole attracts objects and the south pole repeal object.

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How do you give an example for finding net force?
Crazy boy [7]
--  6 people all trying to push a car out of snow

--  a Tug-o-War with 30 people of different sizes pulling on each end of the rope

--  you and your sister both pulling on the same doll (or Transformer)

--  lifting a book up from the table to a high shelf
    taking a book down from a high shelf to the table
    (one force is you; another force is gravity)

--  grabbing your big dog by his collar and trying to bring him inside

--  three people at the table all grab the ketchup bottle at the same time
7 0
3 years ago
If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
sdas [7]
Data:
f_{2} = 42 Hz
n (Wave node)
V (Wave belly) 
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
f_{n} =  \frac{nV}{2L}

Wire 2 → 2º Harmonic → n = 2

f_{n} = \frac{nV}{2L}
f_{2} = \frac{2V}{2L} &#10;
2V =  f_{2} *2L
V =  \frac{ f_{2}*2L }{2}
V =  \frac{42*2L}{2}
V =  \frac{84L}{2}
V = 42L

Wire 1 → 1º Harmonic or Fundamental rope → n = 1


f_{n} = \frac{nV}{2L}
f_{1} = \frac{1V}{2L}
f_{1} =  \frac{V}{2L}

If, We have:
V = 42L
Soon:
f_{1} = \frac{V}{2L}
f_{1} = \frac{42L}{2L}
\boxed{f_{1} = 21 Hz}

Answer:

<span>The fundamental frequency of the string:
</span>21 Hz

7 0
3 years ago
Read 2 more answers
Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it
Kay [80]

<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

F=kx

where, F is the force which is stretching or compressing the spring,

k is the spring constant; and

x is the distance the spring is stretched.

Substituting the given values to find the elastic constant  k to get:

F=kx

4=k(2)

k=\frac{4}{2}

k=2

Therefore, the elastic constant is 2 Newton/cm.

3 0
2 years ago
Some parents build their children’s lives around sports and place a high premium on the successes their children achieve in spor
riadik2000 [5.3K]

Answer:

I think they cross the line when they force sports into their child's life, and take away their choice of what they want to do so they essentially waste their childhood preparing for something that may never happen or they just don't get the opportunity to explore their artistic abilities.

Explanation:

3 0
3 years ago
Gold-leaf electroscope uses
Kruka [31]
-identifies an electric charge 
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-can identify the magnitude of a charge (how big of a charge it is)
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