1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valentina_108 [34]
3 years ago
7

Identify the ion ratios needed to form neutral compounds from the ions below. The metal ion (cation) is listed first, and the no

nmetal ion (anion) is listed second. Make sure to give each ratio in its most simplified form.
Na+:Br– = 1 :
Answer: One

Al3+:Cl– = 1 :
Answer: Three

Mg2+:O2– = 1 :
Answer: One

Al3+:O2– = 2 :
Answer: Three

(I found the answers in the end, so if anybody is in need of the answers I filled them in)
Chemistry
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

1 3 1 3

Explanation:

thank you

ad-work [718]3 years ago
3 0
Here are the ratios,

For,
                                                  Na⁺¹ and Br⁻¹
                                                     1     :     1
So,
                                                         NaBr


For,
                                                  Al⁺³ and Cl⁻¹
                                                     1     :     3
So,
                                                         AlCl₃


For,
                                                  Mg⁺² and O⁻²
                                                     2     :     2
Or,                                                 1     :     1
So,
                                                         <span>MgO
</span>

For,
                                                  Al⁺³ and O⁻²
                                                     2     :     3
So,
                                                         Al₂O₃


You might be interested in
Who created the underlying technology utilized in nike
Ne4ueva [31]

Answer:

Rudy

Explanation:

6 0
3 years ago
Read 2 more answers
The independent variable is the only factor that a scientist
Eva8 [605]
Changes. the dependent variable is affected by the independent variable
3 0
3 years ago
Read 2 more answers
Which of the following most likely happens when thermal energy is removed from a chemical reaction? Rate of reaction becomes fas
3241004551 [841]
If you remove thermal heat from the reaction the reaction will slow down.  meaning that there will be fewer collisions occurring between the particles.
<span />
5 0
3 years ago
Read 2 more answers
GeF 3H is formed from GeH 4 and GeF 4 in the combination reaction: GeH 4 3GeF 4 4GeF 3H If the reaction yield is 92.6%, how many
Olin [163]

Answer:

6.48

Explanation:

GeH4 + 3 GeF4 > 4 GeF3H

3 moles of GeF4 react to form 4 moles of GeF4

Therefore, (8 x 3/4)/0.926

= 6.48 moles

4 0
4 years ago
Chromium has an atomic mass of 51.9961 u and consists of four isotopes, 50 Cr , 52 Cr , 53 Cr , and 54 Cr . The 52 Cr isotope ha
Troyanec [42]

Answer : The atomic mass of _{24}^{53}\textrm{Cr} isotope is 52.8367 amu

Explanation :

We know that:

Total percentage abundance of the isotope = 100 %

Percentage abundance of _{24}^{50}\text{Cr}\text{ and }_{24}^{53}\textrm{Cr}\text{ isotopes}=[100-(83.79+2.37)]=13.84\%

We are given:

Ratio of _{24}^{50}\textrm{Cr}\text{ and }_{24}^{53}\textrm{Cr} isotopes = 0.4579 : 1

Percentage abundance of _{24}^{50}\textrm{Cr} isotope = \frac{0.4579}{(0.4579+1)}\times 13.84\%=4.37\%

Percentage abundance of _{24}^{53}\textrm{Cr} isotope = \frac{1}{(0.4579+1)}\times 13.84\%=9.49\%

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the mass of _{24}^{53}\textrm{Cr} isotope be 'x'

For _{24}^{50}\textrm{Cr} isotope:

Mass of _{24}^{50}\textrm{Cr} isotope = 49.9460 amu

Percentage abundance of _{24}^{50}\textrm{Cr} = 4.37 %

Fractional abundance of _{24}^{50}\textrm{Cr} isotope = 0.0437

For _{24}^{52}\textrm{Cr} isotope:

Mass of _{24}^{52}\textrm{Cr} isotope = 51.9405 amu

Percentage abundance of _{24}^{52}\textrm{Cr} isotope = 83.79 %

Fractional abundance of _{24}^{52}\textrm{Cr} isotope = 0.8379

or _{24}^{53}\textrm{Cr} isotope:

Mass of _{24}^{53}\textrm{Cr} isotope = x amu

Percentage abundance of _{24}^{53}\textrm{Cr} isotope = 9.49 %

Fractional abundance of _{24}^{53}\textrm{Cr} isotope = 0.0949

For _{24}^{54}\textrm{Cr} isotope:

Mass of _{24}^{54}\textrm{Cr} isotope = 53.9389 amu

Percentage abundance of _{24}^{54}\textrm{Cr} isotope = 2.37 %

Fractional abundance of _{24}^{54}\textrm{Cr} isotope = 0.0237

Average atomic mass of chromium = 51.9961 amu

Putting values in equation 1, we get:

51.9961=[(49.9460\times 0.0437)+(51.9405\times 0.8379)+(x\times 0.0949)+(53.9389\times 0.0237)]\\\\x=52.8367amu

Hence, the atomic mass of _{24}^{53}\textrm{Cr} isotope is 52.8367 amu

4 0
4 years ago
Other questions:
  • 1. Write the balanced chemical equation for the synthesis of magnesium phosphide from its elements, including the word “energy”
    12·1 answer
  • Parents should avoid sharing their own mistakes with children. True/false
    6·2 answers
  • 17. Which of the following is true about an electrolytic cell?
    11·1 answer
  • As the two parental (template) DNA strands separate at a replication fork, each of the strands is separately copied by a DNA pol
    5·1 answer
  • What is the difference between dioxide and oxide
    6·2 answers
  • Calculate the mass in 4.05*10^22 molecules of calcium phosphate
    9·1 answer
  • PLEASEEEE HELPPP 15 points
    11·1 answer
  • Compounds and mixtures are both types of substances that contain different types of atoms. Alena is given a sample of material t
    6·1 answer
  • if 3.26 g of FeNO33 is dissolved in enough water to make exactly what is the molar concentration of nitrate ion g
    8·1 answer
  • Which of the drawings contain a mixture?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!