Get your periodic Table and look for the atomic mass of carbon and oxygen and add them to get the answer.
Answer:
The spectroscope scale is illuminated so that one can know exactly where the wavelengths of the lines are falling along.
Answer:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Explanation:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Answer:
1230
Explanation:
1.20×1025=1230 is your answer
Answer:
16.68 m/s
Explanation:
The following data were obtained from the question:
Height (h) = 14.2 m
Initial Velocity (u) = 0 m/s
Final velocity (v) =?
Thus, the velocity (v) with which the ball hit the ground can be obtained as follow:
v² = u² + 2gh
NOTE: the acceleration due to gravity (g) = 9.8 m/s²
v² = u² + 2gh
v² = 0² + 2 × 9.8 × 14.2
v² = 0 + 278.32
v² = 278.32
Take the square root of both side
v = √278.32
v = 16.68 m/s
Therefore, the velocity with which the ball hit the ground is 16.68 m/s