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kirill115 [55]
1 year ago
8

(b) Why is the heat of sublimation ( ΔH fus ) of a substance greater than its ( ΔHvap ) ?

Chemistry
1 answer:
Ivanshal [37]1 year ago
7 0

This is because solids have less energy than liquids do, hence it takes more energy to excite a solid into its gaseous phase than it does a liquid.

When opposed to merely reducing their separation, from solid to liquid, the energy needed to totally separate the molecules as they move from liquid to gas is substantially higher. The latent heat of vaporization is therefore bigger than the latent heat of fusion for this reason.

<h3>What is heat of sublimation?</h3>

The amount of energy required to change one mole of a substance from its solid to its gaseous state under particular conditions—typically the standard ones—is known as the enthalpy of sublimation or heat of sublimation (STP). A solid's worth is based on its cohesive energy.

<h3>What is heat of vaporization?</h3>

The term "enthalpy of vaporization," which is often referred to as "heat of vaporization" or "heat of evaporation," refers to the amount of energy that must be applied to a liquid substance in order to cause a part of that substance to transform into a gas. Vaporization's enthalpy varies with the pressure at which the transition takes place.

Learn more about heat of sublimation: brainly.com/question/13200793

#SPJ4

The correct question is:

Why heat of the sublimation of a substance is greater than the heat of vaporization?

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5 0
2 years ago
A 6.0 M HCl solution is available. What volume is needed to make 6.00 L of 1.00 M<br> solution?
Ket [755]

Answer:

The volume of the stock solution needed is 1L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Concentration of stock solution (C1) = 6M

Volume of stock solution needed (V1) =?

Concentration of diluted solution (C2) = 1M

Volume of diluted solution (V2) = 6L

Step 2:

Determination of the volume of the stock solution needed.

With the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:

C1V1 = C2V2

6 x V1 = 1 x 6

Divide both side by 6

V1 = 6/6

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5 0
3 years ago
Which is a property of water
Paha777 [63]

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6 0
3 years ago
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
Pani-rosa [81]

Answer:

666,480 Joules or 669.48 kJ

Explanation:

We are given;

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but, density of water is 1 g/ml

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  • Initial temperature as 20 °C
  • Final temperature as 99.7° C

Required to determine the heat change

We know that ;

Heat change = Mass × Temperature change × specific heat

In this case;

Specific heat of water is 4.2 J/g°C

Temperature change is 79.7 °C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

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Thus, the heat change involved is 666,480 Joules or 669.48 kJ

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3 years ago
The wavelength of light is 310. nm; calculate the frequency.
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Frequency = velocity of propagation / wavelength. 

<span>For light, we assume it is moving in a vacuum, so vp is 3e8 m/s. The wavelength of 310nm is 310e-9 meters. Then we plug the numbers in, and we get (3e8 m/s) / (310e-9 m) = 967.742e12 Hz because 1/s is the same as cycles/sec, which is a Hertz.</span>
4 0
3 years ago
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